通过循环计算1-100之间,能够被3整除并且被7整除的数字的乘积-搜答案-智慧作业帮

#!/bin/bashsum=0i=2while(($i

#includeusingnamespacestd;voidmain(){inti,sum=0;for(i=2;i再问：i=2的话开始sum不应该等于1么？再答：最后输出的时候加了1，当然你在前面

publicclassTest{publicstaticvoidmain(String[]args){ints1=0;ints2=0;for(inti=1;i

DimiAsIntegerFori=0To100i=i+1NextResponse.Write(i)

////////////////////下面是whileintsum=0;int_i=0;while(_i

intn=1;intsum=0do{if(n%3==0)sum+=n;n++;}while(n

#includeusingnamespacestd;intmain(){intsum=0;for(inti=1;i

Germanyhassaved64.1billionJoelenaturalenergybyrecyclingabandonedpackage,whenitisexchangedintoelectri

publicvoidmod(){inti=1;while(i++

菊花妹,这个就是答案,采纳public class ReplaceNumber{\x09public static void main (&

C语言的.#include"stdio.h"main(){floatn=0;floatsum=0;for(;n

sum1=0;>>sum2=0;>>fori=1:100if(mod(i,2)==1)sum1=sum1+i;elsesum2=sum2+i;endend>>[sum1sum2]ans=2500255

%在matlab中新建一个M文件,将下面这段代码复制进去,保存,文件名自动是sss,不用管,直接确定,再在matlab命令窗口中输入sss就能看到结果,a中装的是删除21整除的数之后的行向量,m中装的

clearx=0y=0dowhilex

我的代码：publicclassTest{publicstaticvoidmain(String[]args){inti=1;intsum=0;while(i

#includemin(){intsum=0,i;for(i=1;i

for(inti=1;i再问：{cout

int sum = 0;for (int i = 0; i != 100; i++){&n

#includeintmain(){intsum=0;intn,i;scanf("%d",&n);for(i=0;i再问：提交时检测显示编译错误再答：#include<stdio.h>&n

;1to100includeio32.inc.datamsg1byte'Pleaseinputanumber(1350):',0msg2byte'Thissumis:',0.codestart:mov