作业帮输出1到1000之内能被5或13整除.但不能同时被5和13整除的整数,
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/26 10:52:20
#includemain(){inti;for(i=10;i再问：能留个QQ吗？有很多问题想请教下你
count==3时会打印两遍可以改成：if ( count == 3 ) { System.o
//测试通过#includemain(){\x09inti;\x09for(i=10;i
for(i=10;
stringstr="";for(inti=1;i
voidfun(int*a,int*n){inti,j,k;*n=0;for(i=1,j=1,k=1;i
voidCountValue(int*a,int*n){*n=Count(a);}intCount(int*array){/////ValueDesignintNumber=1;intDivisibl
#include#includevoidfun(){inti,k,a[300];for(i=0;i
inta[1000];intk=0;for(inti=1;i
intk;*n=0;for(k=1;k
RemLanguage:QuickBASICExtended7.1 i=1 Do Ifimod3=0Orimod7=0Then&nbs
是16个.(61,121,181,241,301,361,421,481,541,601,661,721,781,841,901,961)
#include#includeusingnamespacestd;boolDivided(intn,inti,intj){//判断n是否同时被i和j整除if(n%i==0&&n%j==0)re
#include<stdio.h>void fun (int *a, int *n){ &n
publicstaticvoidmain(String[]args){for(inti=0;i
intsum=0;for(inti=9;i
#includeinta[50];intfun(intm){intn=0;for(inti=1;i
1vari,c11,c7:integer;beginc11:=0;c7:=0;fori:=1to100doifimod11=0theninc(c11)elseifimod7=0theninc(c7);
PrivateSubForm_Load()ForI=1To1000IfIMod7=0ThenX=X+1IfXMod10=0ThenLabel1.Caption=Label1.Caption&vbNew
#includeintmain(){inti;intsum=0;for(i=1;i{if(0!=i%7){sum+=i;}}printf("sum=%d\n",sum);return0;}