输入圆半径,计算输出圆周长和面积,结果保留2位小数(圆周率pi取3.14).

classCircle{private:intm_nR;public:Circle(intnR){m_nR=nR;}floatOutputF(){return2*3.1415926*(float)m_

太水了,按你写的输入输出格式声明变量,然后把这几行输入输出格式都写在主函数里

varch:char;//第一行输入的字符r,x,y,z,a,b:longint;//r为半径,x,y,z为三角形边长,a,b为长宽p:double;//p为海伦公式里的一个量beginreadln(

#include#definePI3.1415926\x05\x05voidmain()\x05{\x05doubler,s;scanf("%f",&r);s=PI*r*r;\x05printf("A

#include#includeusingnamespacestd;classCircle{doubler,Area,Circumference;public:Circle(doublea=0);Ci

是用C语言么?求采纳

#includeusingnamespacestd;classcircle{private:doubleradius;public:circle(doubler=0.0);voidinput();do

PrivateSubCommand1_Click()DimbjAsSingleDimzzAsSingleDimmjAsSinglebj=CSng(Text1.Text)Ifbj

#include#include#defineP3.14doublearea(doubler){returnP*r*r;}doubleCircumference(doubler){return2*P*

#include#definepai3.15149256voidmain(){doubler,c,s;printf("pleaseinputr\n")scanf("%lf",&r);printf("c

doubler,h,c,s,t,v,sv;sacnf("%f%f\n",&r,&h);c=2*3.14*r;s=3.14*r*r;t=4*3.14*r*r;v=(4/3)*3.14*r*r*r;sv=

ConstPI=3.14159DimrAsDoubleDimCAsDoubleDimSAsDoubleIfIsNumeric(Text1.Text)Thenr=Val(Text1.Text)C=2*P

#include"stdafx.h"#include#includeusingnamespacestd;classCircle{doubler,Area,Circumference;public:Ci

周长=直径X3.14

constpi=3.1416subcircle（byvalrassingle,Lassingle,aassingle,VASSINGLE）L=2*pi*rA=pi*r*rV=4/3*r*r*r*pie

#includeclasscircle{private:intr;public:voidinput(){cout

input"输入半径:"torc=2*3.14*rs=3.14*r*rv=4*3.14*r^3/3?"圆周长=",c?"圆面积=",s?"球体积=",v

#include#definePI3.14159main(){\x09intr,h;\x09floats,vz;\x09scanf("%d%d",&r,&h);s=r*r*PI;\x09vz=s*h;

1.#include#include#definepi3.1415926voidmain(){doublex,y,z;scanf("%lf",&x);if(x>0)y=2*pi*x;z=pi*x*x；

#include#includeusingnamespacestd;//圆周率constdoublePI=acos(-1);intmain(intargc,char*argv[]){\x05doubl