输入任意整数n,调用函数int 完成对该整数n各位数字求和

#includeintsum(intn){ints=0;while(n){s+=n%10;n/=10;}returns;}intmain(void){ints=0;for(int

#includevoidsx(intx[],intn){inti,j,t;for(i=0;i

#includeintmax(inta,intb){returna>ba:b;}voidmain(){inta,b;scanf("%d,%d",&a,&b);printf("%d\n",max(a,b

#include<stdio.h>int getmax(int a,int b){      re

#include#includeintmax(inta,intb){if(a>=b){returna;}else{returnb;}}intmain(intargc,constchar*argv[])

#includeinteven(inta){if(a%2==0)return1;elsereturn0;}voidmain(void){intnum,odd=0;printf("请输入一批整数,以零或

intjc(intx){returnx==1?1:jc(x-1)*x;}再问：可以编一个完整的么？我直接运行试一下。。。新手，不好意思，，，，谢谢再答：intjc(intx){returnx==1?1

intjioushu(intn){if(n%2!=0)return(1);elsereturn(0);}voidmain(){intn=11;printf("请输入一个数：");scanf("%d",

VC++编程#includeusingnamespacestd;intmax(intx,inty);//子函数的声明,子函数的参数的类型intmain(){intMAX,x,y;cin>>x>>y;M

vars,ans:int64;i:longint;beginreadln(s);fori:=1tosdoinc(ans,facto(i));writeln(ans);end.也许需要高精度!当s>=1

#includeintStrchr(chars[],charch){intl,i;intj=0;l=strlen(s);for(i=0;i

#includeintgcd(intm,intn){\x09intr;\x09do\x09{\x09\x09r=m%n;\x09\x09m=n;\x09\x09n=r;\x09}while(r!=0)

#includevoidsort(inta[],intsize){intj,n,b;for(j=0;j

intsum(intn){if(0>n){n=-n;}intsum=0;while(0!=n){sum+=n%10;n/=10;}returnsum;}

#includevoidmain(){inta,b,num1,num2,temp;scanf("%d%d",&num1,&num2);if(num1

#includemain(){longintn,i,j,k;doublem;printf("请输入数字'n':");scanf("%d",&n);if(n%2==1){for（i=0;i0){for（

什么事指针函数?不知道这个但是完成上面的题貌似很简单

java版实现public class Calculator{    public int calTest(int&nb

voidfun(inta[5],intn)相当于voidfun(inta[],intn);或者voidfun(int*a,intn)D中b[0]是int型,和int*a明显类型不一致.再问：那Cfun

#includeintGcd(intM,intN){intRem;while(N>0){Rem=M%N;M=N;N=Rem;}returnM;}voidmain(){inta,b