输入任意N个数,计算它们的和.积.平均值.
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//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(
再简化一下#include#defineN10voidmain(){inta[N],i,s1=0,s2=0;for(i=0;i
1.int的范围太小,可能题目的n会比较大,用long试试,还不行的话换longlong;2.题目说了不包括n,你的代码里面包括了n;3.输出格式方面,最后最好输出一个换行符.#includeintm
VC6.0调试通过了,while循环结构#include"stdio.h"voidmain(){inti,sum=0,n;i=1;printf("Inputn:");scanf("%d",&n);wh
#include <stdio.h>;int main(int argc, char **argv) {
#include#includeintmain(void){intn,m,i,j,t;scanf("%d%d",&n,&m);i=m>n?m:n;j=m>n?n:m;while(j){t=i%j;i=
#include#defineN100intmain(){inta[N],i,j,count1,count2;floatave1,ave2;count1=count2=ave1=ave2=0;for(
scanf("d%",&a);应该是scanf("%d",&a);吧还有既然是判断正数和负数,是不是应该加入输入“0”要求重新输入呢
clears=0a="y"dowhilea="y"ora="Y"input"请输入一个数:"toxs=s+xwait"是否继续输入数据(Y/N)?"toaenddo?"它们的和是:",s
dimiasinteger,nasinteger,sasinteger,kasintegerfori=1to10k=val(inputbox("请输入一个整数:"))ifkmod2=1thenn=n+
#includevoidmain(){inti,n,m,jh=0,oh=0,jg=0,og=0;printf("请输入n的值:\n");scanf("%d",&n);//先输入数据个数nprintf(
#includeintmain(){floatget=0;intPosNum=0;intNegNum=0;floatPosSum=0;floatNegSum=0;printf("pleaseinput
publicstaticvoidtest(){Scannersc=newScanner(System.in);longnum=0,negative=0,positive=0,sum=0;Listnum
publicclassTestNum{publicstaticvoidmain(String[]args){Scannersca=newScanner(System.in);intnum=0;ints
#includevoidmain(){intn,m[20],i,j=0;intA=0,B=0,C;scanf("%d\n",&n);for(i=0;i
参考程序:Programcount;Vara,b,c,n,m,i:integer;BeginRead(n);a:=0;b:=0;c:=0;Fori:=1TonDoBeginRead(m);IfmMod
#include#defineN10voidmain(){inta[N],i,s1=0,s2=0;for(i=0;i
#include#include#defineMAX1000intmain(){inta[MAX],i,j,n,p,q,s1,s2;p=0;q=0;s1=0;s2=0;printf("请输入要输入的值
#includevoidmain(){intn,i,ji=0,ou=0;//ji用来统计奇数的个数,ou用来统计偶数的个数intinput,jihe=0,ouhe=0;//jihe用来统计奇数的和,o