输入五位以内的正整数,输出它为几位,倒叙打印出每一位

voidmain(){intn=-1;while(n

main(){longinta;intb,c,d,e,f;scanf("%ld",&a);while(a>=1&&a=1&&a/10000=1&&a/1000=1&&a/100=1&&a/10=1&&

intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+

#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}

核心代码Scanners=newScanner(System.in);doubleresult;while(s.hasNextInt()){inti=s.nextInt();if(i/2==1){re

#includeintmain(){intm[10],i,j=0,k;longn;scanf("%ld",&n);k=n;while(k>0){k/=10;j++;}i=j;while(i--){m[

#includevoidmain(){inta,i=0,b[3];printf("inputathreebitnumber\n");scanf("%d",&a);if(a>=100&&a=0;j--)

programlong;vari,n:integer;beginreadln(n);whilen0dobeginwrite(nmod10,'');n:=ndiv10;end;writeln;end.

#include"stdio.h"voidmain(){inti=1;intn;printf("请输入n");scanf("%d",&n);for(i=1;i再问：我知道了在FOR循环后面再加以个pr

input "输入一个数：" to srsrc=ALLTRIM(STR(sr))lensr=LEN(src)yxsr=""FOR&

#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol

#includeusingnamespacestd;voidmain(){intnum,reverse=0,count=0;while(1){coutnum;//输入数据if(cin.bad()||n

能够把题目描述得清楚一些,看不明白啊?或者加个输入输出的样列也好啊.如果你描述清楚,我直接给你源程序.

Dimn%,cs,i%n=Text1cs="1":i=2DoIfnModi=0Thenn=n/i:cs=cs&"×"&iElsei=i+1EndIfLoopWhileiOptionExplicitPr

#include <stdio.h>//最大的精度#define MAX_LENGTH 120//计算商int GetFactor(int 

#include#includeintmain(void){\x09chara[20];\x09printf("请输入数字");\x09scanf("%s",a);\x09printf("%c",a[

vari,j,n:longint;z:boolean;beginreadln(n);writeln(2);fori:=3tondobeginz:=true;forj:=2toi-1doifimodj=

classProgram{staticvoidMain(string[]args){intM;stringS=Console.ReadLine();boolTorF=int.TryParse(S,ou

intprime(intx){\x09inti;\x09for(i=2;i

#include#defineMAXN20intmain(){intn,t,k=0;intia[MAXN];printf("请输入一个整数:");scanf("%d",&n);while(t=n%10