输入两个整数num1和num2,计算并输出它们的和.差.积.商与余数.

print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Enternum1=");scanf("%d",

用什么语言编写再问：c语言

importjava.util.Scanner;publicclassTest20010{publicstaticvoidmain(Stringargs[]){\x05intnum1,num2;\x05Scannerin=newScanne

程序如下：#includevoidmain(){\x05intnum1,num2,sum,min,mul,yushu;\x05floatshang;\x05scanf("%d",&num1);\x05scanf("%d",&num2);\x

intnum1,num2,i,sum=0;scanf(%d%d,&num1,&num2);for(i=num1;i

sum=0;num=num1;do{num++;if(num|2)sum+=num;}while(num再问：似乎不对啊！再答：intnum1;intnum2;cin>>num1;cin>>num2;intsum=0;intnum=num1

#includevoidmain(){inta,b;printf("pleaseinputtwonums:");scanf("%d%d",&a,&b);printf("%d%d\n",a/b,a%b);}

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);printf("差:a-b=%d\n",a

intmax_common_divisor(inta,intb){//最大公约数intlarge_num,small_num,r;if(a>b){large_num=a;small_num=b;}else{large_num=b;small

intnum1,num2,num3,num4；num1=num2=num3=num4=0；

我不会啊啊

枚举法r0temp(a,temp(b,c))

（1）解决此问题的算法是解析法.（选填：解析法或枚举法）在程序①和②划线处,填入适当的语句或表达式,把程序补充完整：（2）程序中①划线处应填入r0.（3）程序中②划线处应填入temp(a,b).

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);inta=0;intb=0

//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(min

#includeintmain(void){\x09intnum,i,j,k,sum;\x09printf("输入一个三位整数!\n");\x09scanf("%d",&num);\x09i=num%10;num=num/10;\x09j=

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespaceCompare_Number{classProgram{stati

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09printf("商为%.2f余数为%d\n",1.0*a/b,a%b);\x09return0;}

#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i

#includeintmain(){floatf1,f2;inti1,i2;printf("输入2个数\n");scanf("%f,%f",&f1,&f2);printf("f1+f2=%.2f\n",f1+f2);printf("f1-f