输入一整数,打印出它是奇数还是偶数
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 06:04:46
#includevoidmain(){intn;printf("输入一个整数:");scanf("%d",&n);if(n%2==0){printf("%d是偶数\n",n);}else{printf
#includevoidmain(){inta;printf("Pleaseinputanumber:");scanf("%d",&a);if(a==0)printf("%disaevennumber
#includeintfun(intn){inti,j;for(i=2;i
#include"stdio.h"voidmain(){inti,j,k,n,a[25];printf("请输入一个数:\n");scanf("%d",&k);if(k/2==(float)k/2)\
#includevoidmain(){inta;printf("输入一个三位数");scanf("%d",&a);printf("百位:%d十位:%d个位:%d\n",a/100,a/10%10,a%
用那个数除以2,判断是不是整数,是的话就是偶数追问:从键盘读入一个整数,计算该数字的各位数字之间之和,并显示结果.例如:从键盘读入整数为123,其各位之和为1+2+3=6程序员设计题求答案回答:不会呀
main(){inti;scanf("%d",&i);if(i%2)printf("JISHU");elseprintf("OUSHU&quo
intx;if(x%2==1){System.out.print("奇数");}else{System.out.print("偶"}大致意思你应该能看懂吧!我用手机打得会有些语法错误!定义得x就是输入
你写的实在是太繁琐了.这个是不可取的.你需要的这两个功能其实是可以一起实现的,虽然一楼说的很对,当我觉得应该不是你需要的那一种方案.#includemain(){inti=0,k;inta[10;pr
楼上是C语言的.我补充VB的.设你的数是num(整型).a=nummod2若a=1则num为奇数,若a=0则num为偶数.
c:voida(inti){if(i%2==0)printf("偶数");elseprintf("奇数");}手写的,没调试
#include"stdio.h"intmain(){inta;printf("Pleaseinput:\n");scanf("%d",&a);if(a%2){printf("%d是奇数",a);}e
#includeintjudge(intnum){returnnum%2==0?0:1;}main(){intn;while(scanf("%d",&n)!=EOF){if(judge(n))prin
#includeintmain(void){inti;scanf("%d",&i);if(i%2==0)printf("it'saEven");/*输出偶数*/elseprintf("it'saodd
/*从键盘上输入一个任意位数的正整数,判断它是几位数,并逆序输出该数*/#include"stdio.h"intmain(){intnum,temp,i=0;printf("请输入一个数字\n");s
#includeusingnamespacestd;voidmain(){intn;cin>>n;if(n%2==0)cout
请问用什么语言编写?再问:我的失误!用C#
Subtest()OnErrorGoTo10n=InputBox("输入一个整数")MsgBoxIIf(nMod2=0,"你输入的是个偶数","你输入的是个奇数"):ExitSub10:MsgBox"
#includeusingnamespacestd;boolpanduan(intn){intm=n%2;if(m==0)returntrue;elsereturnfalse;}intmain(){i
#includemain(){intnum,yushu;printf("Pleaseenterthenumber\n");scanf("%d",&num);yushu=num%2;if(yushu==