输入一批整数,先求出其中的偶数和及奇数和,然后输出偶数和与奇数的差 C语言编程
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/09 07:54:04
#includeintmain{inti;inta1,a2,a3;printf("输入三个数:\n");scanf("%d%d%d",&a1,&a2,&a3);if(a1>a2)i=a1;elsei=
#includemain(){inta,b,c,d,max,min;scanf("%d,%d,%d,%d",&a,&b,&c,&d);max=a;min=a;if(b>max)max=b;if(c>m
//仅供参考#includeintmain(){intn,sum=0;while(scanf("%d",&n)==1&&n+1){if(n%2==0)printf("%d\n",n);elsesum+
#includevoidmain(){inta[10],i,sum=0,count=0;printf("请输入10个整数:\n");for(i=0;i再问:奇数输出不了 再答:不好意思,我是
#includeusingnamespacestd;voidmain(){cout
你的i, j赋上初值为0你求平均不用在循环体里算的, 只需统计i, j的值就行了, 跳出循环的时候算一次就OK了.另外,你求平均,av1,av2就要用float
#include "stdio.h"int main(){ int count1=0,count2=0,i;&nbs
#includeintmain(){inti,j,sum1,sum2;inta[1000],n;sum1=sum2=0;//分别记录偶数和奇数的和scanf("%d",&n);//记录整数个数
inta,index;inti;while(1){cout
#include#includeintmain(){inta,sum1=0,sum2=0;printf("putdata");while(scanf("%d",&a)!=0){if(a%2==0)su
#includevoidmain(){inta[10],i=0,j=0;intmax1=0,max2=0,tmp=0;printf("Pleaseinputnumbers:");for(i=0;i再问
同学你是女的吧,我亲自来指导你~
#includeintmain(intargc,charconst*argv[]){intnumbers[20];inti,sum=0,count=0;for(i=0;i{scanf("%d",&nu
publicstaticvoidmain(String[]args){intarray[]=newint[20];intresult=0;Listlist=newArrayList();System.
int[]num=newint[4];inti,j;inttemp;Console.WriteLine("请输入4个数");for(i=0;iConsole.WriteLine("第{0}个数",(i
.你把做为结束符的0也算进去了吧.在循环里判定一下,如果是0不做MIN==NUMif(NUM!=0)MIN=MIN
#includevoidmain(){\x09\x09inti,a,n,j=0;\x09floats=0;\x09\x09\x09printf("请输入整数的个数:");\x09scanf("%d",
#include#includeintmain(){inta,sum=0;do{scanf("%d",&a);if((a/100)%10==3)sum+=a;}while(a!=0);printf("
inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=
publicclassDemo{publicstaticvoidmain(Stringargs[]){int[]nums={5,2,45,11,13,32,7,24,63,48};intodd=0,e