输入一个整数判断是奇数还是偶数

#includevoidmain(){intn;printf("输入一个整数：");scanf("%d",&n);if(n%2==0){printf("%d是偶数\n",n);}else{printf

voidmain(){inta;scanf("%d",&a);if(a%2==0){printf("偶数");}else{printf("奇数");}}programJO;vara:integer;b

#includeintmain(){intn;printf("请输入一个整数:");scanf("%d",&n);if(n>0){if(n%2)printf("正奇数\n");elseprintf("

#include <stdio.h>void main(){    int n;   &

#includevoidmain(){inta;printf("Pleaseinputanumber:");scanf("%d",&a);if(a==0)printf("%disaevennumber

用那个数除以2,判断是不是整数,是的话就是偶数追问：从键盘读入一个整数,计算该数字的各位数字之间之和,并显示结果.例如：从键盘读入整数为123,其各位之和为1+2+3=6程序员设计题求答案回答：不会呀

不知道楼主的编译器是不是和我的一样,不支持longdouble类型,我的改成这样就可以了：#include <stdio.h>int main(void){\x05do

楼上是C语言的.我补充VB的.设你的数是num（整型）.a=nummod2若a=1则num为奇数,若a=0则num为偶数.

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#includeintmain(void){longi;printf("请输入要判断的数\n");scanf("%ld",&i);if(i%2==0){printf("您输入的%ld是偶数\n",i)

#includeintjudge(intnum){returnnum%2==0?0:1;}main(){intn;while(scanf("%d",&n)!=EOF){if(judge(n))prin

#includeintmain(void){inti;scanf("%d",&i);if(i%2==0)printf("it'saEven");/*输出偶数*/elseprintf("it'saodd

#includeusingnamespacestd;voidmain(){intn;cin>>n;if(n%2==0)cout

importjavax.swing.JOptionpane;//导入JOptionpane类.publicclassTest{publicstaticvoidmain（Stringargs[]）{in

#include"stdio.h"main(){intx;printf("请输入一个整数");scanf("%d",&x);if(x%2==0)printf("%d是偶数\n",x);elseprin

Subtest()OnErrorGoTo10n=InputBox("输入一个整数")MsgBoxIIf(nMod2=0,"你输入的是个偶数","你输入的是个奇数"):ExitSub10:MsgBox"

写个函数吧：intfunction(intx){if(x%2==0)return1;//当整数X除2取余为零时,返回1,即为偶数elsereturn0;//当整数X除2取余不为零时,返回0,即为奇数}

Functionoushu(ByvalnAsInteger)AsBooleanIfnMod2=0Thenoushu=TrueElseoushu=FalseEndFunctionFunctionEven

#includeusingnamespacestd;boolpanduan(intn){intm=n%2;if(m==0)returntrue;elsereturnfalse;}intmain(){i

#includemain(){intnum,yushu;printf("Pleaseenterthenumber\n");scanf("%d",&num);yushu=num%2;if(yushu==