输入一个四位数,请将该数逆序输出. 如:输入1234,程序输出4321.

#includevoidmain(){inti;printf("pleaseinputanumberbetween0and1000:");scanf("%d",&i);if(i>1000||i=100

PrivateFunctionFunc(ByValSAsString)AsByteIfLen(S)4ThenExitFunctionFunc=Val(Left$(S,1))+Val(Mid$(S,3,

intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+

stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons

C语言?#include"stdio.h"intmain(){intnum,i=0;printf("请输入一个数字\n");scanf("%d",&num);while(num){\x05++i;\x

/*12342103Pressanykeytocontinue*/#include<iostream.h>int main() {\x09int digit1

intmain(void){\x05intn;\x05intcount=0;\x05inta,b,c,d,e;\x05printf("请输入一个不低於5位的正整数：");\x05scanf("%d",

规定利用Mod跟“/”来编码廷垃圾的,本来两个函数就搞定了.PrivateSubCommand1_Click()DimaAsInteger,bAsInteger,cAsIntegerDimiAsInt

不知道你是要用什么语言编程.这里提供一个C小程序,希望能帮上你的忙.#include"stdafx.h"#include"iomanip.h"voidmain(void){intnin;cout>ni

1089,四位数首位为1,如此则末位为9,第二位只能是0或1,如为1则第三位为7,那乘9后大于9999,故考虑为0,那则为10x9,逆序数为9x01,得出x为8

第一个：#includeintmain(){intans=0,in;scanf("%d",&in);printf("%d\n",in);ans=in%10;in/=10;while(in/10){an

/*从键盘上输入一个任意位数的正整数,判断它是几位数,并逆序输出该数*/#include"stdio.h"intmain(){intnum,temp,i=0;printf("请输入一个数字\n");s

具体代码如下:#includeintmain(){intn,i=0;printf("Entern:");scanf("%d",&n);while(n){printf("%d",n%10);n/=10;

#include<stdio.h>int main(){int n,s=0;scanf("%d",&n);while(n){s=

#include"stdio.h"#include"conio.h"#defineQ100voiddx(chars[Q])/*自定义函数,功能实现字符串倒叙*/{inti,j;chartemp;for

intflip(intin)//不用数组{intout=0,flag=0;if(in>-10&&inreturnin;elseif(in{flag=1;in=-in;}do{out+=in%10;ou

如该数为m则其十位数为a=m/10整个位数为b=m/10取余

#include#includeusingnamespacestd;voidmain(){chars[4];intn,k;cin>>s;sort(s,s+4);n=(s[0]-'0')*10

#include#includevoidmain(){inti;charstr[100];scanf("%s",&str);printf("长度为:%d\n逆序输出:",strlen(str));fo

#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10