输入一个3位正整数,分别输出它们的个位 十位合百位数字

voidmain(){intn=-1;while(n

//z2.cpp:定义控制台应用程序的入口点.//#include"stdafx.h"#include#includeusingnamespacestd;voidReverse(int&m)//m为4

#includeintmain(){inti,k,n,t;doubleans;scanf("%d",&n);ans=0;t=1;k=1;for(i=1;i再问：输入输出示例Entern;3sum=0.

main(){longinta;intb,c,d,e,f;scanf("%ld",&a);while(a>=1&&a=1&&a/10000=1&&a/1000=1&&a/100=1&&a/10=1&&

intmain(){intn,n1,n2,n3,n4;cin>>n;n1=n/1000;n2=(n%1000)/100;n3=(n%100)/10;n4=n%10;n=n1+10*n2+100*n3+

#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}

#includevoidmain(){inta,i=0,b[3];printf("inputathreebitnumber\n");scanf("%d",&a);if(a>=100&&a=0;j--)

这个是第一种：#includevoidmain(){inti,j=1,N;printf("请输入N的值：\n");scanf("%d",&N);for(i=1;i

input "输入一个数：" to srsrc=ALLTRIM(STR(sr))lensr=LEN(src)yxsr=""FOR&

#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol

#includeusingnamespacestd;voidmain(){intnum,reverse=0,count=0;while(1){coutnum;//输入数据if(cin.bad()||n

没看懂

能够把题目描述得清楚一些,看不明白啊?或者加个输入输出的样列也好啊.如果你描述清楚,我直接给你源程序.

#includeintmain(void){longintx;inty,i=1;printf("请输入一个不超过100000的整数:");//99999||x

Dimn%,cs,i%n=Text1cs="1":i=2DoIfnModi=0Thenn=n/i:cs=cs&"×"&iElsei=i+1EndIfLoopWhileiOptionExplicitPr

#include"stdio.h"main(){chara[10];inti,j;h:printf("请输入数字,注意不能超过5位:");gets(a);for(i=0;a[i];i++);if(i>

#include#includeintmain(){doublea=1,b=1;doubles=0;inti,n;scanf("%d",&n);for(i=1;i

可以是可以,不过太麻烦了,见下面的代码#includeintmain(){inta,b[5],s=0;scanf("%d",&a);while(a){b[s++]=a%10;a/=10;}printf

classProgram{staticvoidMain(string[]args){intM;stringS=Console.ReadLine();boolTorF=int.TryParse(S,ou

#include#defineMAXN20intmain(){intn,t,k=0;intia[MAXN];printf("请输入一个整数:");scanf("%d",&n);while(t=n%10