输入50个数,输出他们平均值和这些数中所有大于平均数的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/11 18:05:40
#include“stdio.h”#defineMAX100voidmain(){intmark[MAX],sum=0,mark=0,j=0,aver=0;printf("请输入学生成绩,输入负数结束
#includevoidmain(){inta[10],i,count1=0,count2=0,sum1=0,sum2=0;floataverage1,average2;for(i=0;i
mian(){floats1=0,s2=0,x;intn1=0,n2=0,i;for(i=0;i0){s1+=x;n1++;}if(x
#includeintmain(void){intx[10];intsum=0;inti=0;intavg=0;for(i=0;i
假设是用a数组存放的数据intsum=0,i,num=0,average;for(i=0;i
#includeintmain(){inti;doublen[20];doublesum=0.0,average;for(i=0;i
给你写了,你看看吧#includeintmain(void){inta[20],i,j,sum=0,temp;for(i=0;i
#include“stdio.h”main(){floata[20];//这里给20个数开辟存储空间,这里定的是浮点型,//你可以根据自己的需要指定数据类型floatsum=0,avrage;inti
你好! 程序改好了,运行的结果 完整的程序,你看看吧,满意请采纳#include<stdio.h>int ma
#includeintmain(){float*p,*q,*max,*min,ave=0;intn;scanf("%d",&n);q=(float*)calloc(n,sizeof(float));f
#include"stdio.h"intmain(){intnum[21],i,n=0,zh=0,fu=0;floatave;printf("请输入20个整数:\n");for(i=0;iscanf(
voidmaxminaver(){inta,n,i;intmin_val,max_val;doubleaver=0;scanf("%d",&n);if(n>0)for(i=0;i
#include<stdio.h>int main(){ int a[10],i,num=0; float ave
#includemain(){inti,p1=0,p2=0,max,min,num[10];printf("input10numbers:\n\n");scanf("%d",&num[0]);max=
用c语言吧:#includevoidmain(){inti;floata[10],avg,temp1=0,temp2=0,fc;for(i=0;i
给你写个程序吧,pascal已经忘得差不多了.PROGRAMsinfile1(input,output);VARx,s1,s2:real;n1,n2:Integer;BEGINs1:=0;s2:=0;
#includevoidmain(){floata,b,c,d,sum,average;printf("请依次输入4个实数,以空格间隔,以回车键结束:\n");scanf("%f%f%f%f",&a,
#includevoidmain(){inti,b=0;floatp,a[5],sum;for(i=0;i
#includeintmain(){inti,max,ave,a[10];printf("Enter10numbers:\n");ave=0;for(i=0;imax){max=a[i];}}ave/
#include "stdio.h"int main(){ double x,sum=0,ave; int