输入2个正整数a和n,求a aa aaa aa-a(n个a)之和.方案设计-搜答案-智慧作业帮

#include#includelongfac(intn,inta){longsum;if(n==1){sum=a;}else{sum=(long)(pow(10,n-1)*a)+fac(n-1,a)

#include"Stdio.h"main(){intprime(int);intm,n,i,sum=0,count=0;scanf("%d,%d",&m,&n);if(m500)printf("Da

PrivateSubForm_Click()DimaAsIntegerDimnAsIntegerDimsAsStrings=""Randomizea=Int(Rnd()*9)+1n=Int(Rnd()

#includemain(){intn;longa,sum=0;printf("pleaseinputaandn,andpressEntertocontinue\n");scanf("%ld%d",&

把你写的给我看一下再问：#include#includeintmain(void){inti,j,p,m,n,count;count=0;printf("Inputm:");scanf("%d",&m

ints=0;for(inti=0;i

/*2 (repeat=2)2 3 (a=2, n=3)8 5 (a=8, n=5)

intprime(inti){intj;\x05if(i==1)return0;for(j=2;j

C程序设计：输入2个正整数m和n(1<=m,n<=500),统计并输出m和n之间的素数个数以及这些素数的和.输入：m和n；输出：素数个数以及这些素数的和.

当i不等于n的时候在s字符串最后加上一个“+”号,当输出最后一个字符串,比如22222时候i=5,n=5,这个时候不要再s最后加上“+”号如果有这句,比如a=2,n=5时候输出是这样的：当a=2时,n

#includeintmain(){intm,n;inti,j,s,d;printf("请输入m：");scanf("%d",&m);printf("请输入n：");scanf("%d",&n);pr

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没有仔细看,但是有一处有问题,你试试看.if(i=is(i))为什么碰到一个i满足要求时,要将i重新赋值为1呢?!改为：if(is(i))

scanf("%d",&m);加个if判断就行了if(m==1)m=2;

CLOSEALLCLEARALLCLEARcGetLenth_a=""nMaxLenth_n=09&&&n的最大数.***因VFP数字取值范围为：-2147483647到2147483646,即：**

C语言版：includeincludevoidmain(){inta,n,S;inti;printf("a=?\n")scanf("%d",&a);printf("\nn=?\n")scanf("%d

#includeintfact(intn){intt=1;for(inti=1;i

#includeintmain(){intsum,i,j,n,m;scanf("%d%d",&m,&n);inta[6][6];for(i=0;i再问：仍然是0分再答：不是的。你将代码进行调试就可以了

main(){intp,r,n,m,temp;printf("请输入两个正整数n,m:");scanf("%d,%d",&n,&m);if(n{temp=n;n=m;m=temp;}p=n*m;whi

#include<stdio.h>int main(){ int factorsum(int number); &