该数编程,从键盘输入一个数,如果是一个正数,则求出该数的相反数并将结果输出

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

#include#includeintmain(){\x09doublex;\x09scanf("%lf",&x);\x09printf("%lf\n",sqrt(x));\x09return0;}

voidmain(){inta[10];intmax=0;inti;for(i=1;ia[max])max=i;}if(max!=0){i=a[0];a[0]=a[max];a[max]=i;}/*最

stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons

1#include"stdio.h"main(){intn,i;scanf("%d",&n);printf("%d",n/100+n%100/10+n%10);system("PAUSE");}2#i

longsum;sum=0;inta,tmp;a=1;tmp=a;for(inti=0;i

#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a

#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i

我有个matlab的代码,闲来无事就你这个题编的,供你参考吧.a=input('pleaseinputanumber:');j=1;fori=1:9ifa-j

#include"stdio.h"//voidmain(void){inta,b,c;printf("请输入两个十进制整数!\na=");scanf("%d",&a);printf("b=")

#includeintmain(){intnum;inta,b,c;scanf("%d",&num);a=num/100;b=(num%100)/10;c=num%10;printf("a=%d,b=

#includeusingnamespacestd;intmain(){char*str=newchar[255];cin>>str;cout再问：看不等，我刚学编程再答：把输入的数字放到一个指针数组

#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b

inputaifmod(a/2)=0?a/2+3endif

#include"stdafx.h"voidmain(){intnum;printf("输入一个数:");scanf("%d",&num);if(num%3==0){if(num%5==0){prin

oolcalc(unsignedintn){if(n

#includevoidmain(){intn,i,j,k,m;floats=0,t;i=1,j=2;printf("输入n:");scanf("%d",&n);for(m=1;m

#includeintk;voidshow(){chara;printf("Pleaseinputtheletter.\n");scanf("\n%c",&a);printf("Theletter's

#includevoidmain(){intn;sacnf("%d",&n);if(n%27==0)printf("Yes\n");elseprintf("No\n");}

main()　　{inta,b,c;　　printf(“请输入三个整数：”);　　scanf(“%d,%d,%d”,&a,&b,&c);　　if(aif(belseprintf(“max=%d\n”,