设有数列要求编写一个递归函数实现求数列的第n项,再在主函数是求数列的前
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#includeunsignedintFibonacci(intn);intmain(void){inti;for(i=1;i
添加一个文本框输入前N项的N值,再添加一个命令按钮即可PrivateFunctionF(NAsLong)AsLongIfN>2ThenF=F(N-1)+F(N-2)ElseF=1EndIfEndFun
为用了很没有效率的递归,所以出结果有点慢#includeiostream.h
帮你写好了.unsigned int fib(unsigned int n) {\x09if (n == 1
#includelongintfn(int);voidmain(){printf("%d",fn(10));}longintfn(intm){longinttemp;if((1==m)|(2==m))
因为用了很没有效率的递归,所以出结果有点慢#includef(int);main(){inti,s=0;for(i=1;i
很高兴回答你的问题!#includeintfun(intn,intx){if(n==0)return1;intmul=x;for(inti=n;i>1;i--)mul*=x;returnfun(n-1
// C++int F(int n) {if (n == 0) return 1;else if
把以下程序另存为fib.m%>>fib(8)Fibonacci=123456781123581321
用VB写的~PrivateSubForm_Load()Dimfn&,f1&,f2&,n%f1=1:f2=1n=Val(InputBox("请输入n"))fn=f1+f2Printf1Printf2Pr
#includeusingnamespacestd;doublefun(intn,doubleh){if(n==1)returnh;elseif(n再问:usingnamespacestd;这句
#includeintFibonacci(intn){if(n==1||n==2)//递归结束的条件,求前两项return1;elsereturnFibonacci(n-1)+Fibonacci(n-
#includelongfac(intn){inti;longx=1;for(i=2;i再问:谢谢咯!可是我说的是递归法哦!再答:#includelongfac(intn){if(n==0)retur
/>#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;c
#include <stdio.h>char* dg(char* instr, char* outstr, char* 
intSumNums(intnum){if(num
1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n
#includemain(){intn,i,j,k;while(scanf("%d",&n)==1){if(n==1||n==2){printf("%d\n",1);cont
#includeintfibo(intn){if(nreturn1;elsereturnfibo(n-1)+fibo(n-2);}intmain(){intn;scanf("%d",&n);print
#includeusingnamespacestd;longunsignedfun(intn){if(n>1)returnn*fun(n-1);return1;}voidmain(){intn;cou