OE平分角BOD,角AOD-角DOB=80
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∠BOD+∠AOD=180°所以1/2×∠BOD+1/2×∠AOD=90°因为OC,OE分别是∠BOD和∠AOD的角分线所以∠COD=1/2×∠BOD,∠EOD=1/2×∠AOD因为∠COD+∠EOD
自己写、、、再问:..................
∠DOE=54°∠COD=36°解题过程:∠AOB=180°,∠AOD=2∠COD,∠BOD=2∠DOE,∠COD:∠DOC=2:3所以,∠COD=3分之2∠DOE,∠AOB=∠AOD+∠BOD=2∠
∵∠COD是平角=180°∴∠BOD+∠BOC=2∠BOC+30°=180°∴∠BOC=75°∴∠AOD=∠BOC=75°(对顶角相等)又∵OE是角平分线∴∠EOA=37.°5又∵∠AOC=∠BOD=
因为AB与CD相交于点O根据对角相等,所求∠AOC=∠DOB因为CD为直线,O在直线CD上所以∠COD=180°因为∠AOC:∠AOD=7:11所以∠AOC=70°,∠AOD=110°因为∠AOC=∠
因为OC平分角AOD,OE平分角BOD.所以∠AOC=∠COD,∠BOE=∠DOE因为A,O,B在一条直线上,所以∠AOC+∠COD+∠BOE+∠DOE=180度所以∠COD+∠DOE=90度,∠CO
∵AB与CD相交于点O∴∠COB+∠BOD=180°(平角的意义)∵∠BOC=∠BOD-30°(已知)∴∠BOD-30°+∠BOD=180°(等量代换)∴∠BOD=105°(等式性质)∴∠BOC=75
∵OC平分∠AOD,OE平分∠BOD∴∠AOC=∠COD,∠DOE=∠EOB又:∠AOC+∠COD+∠DOE+∠EOB=∠AOB=180°∴∠COD+∠DOE=1/2∠AOB=90°∴∠DOE=90°
角的符号我就不写上来了BOD=AOC=120度(对顶角相等)AOD=180-AOC=180-120=60度(邻补角)OE平分AOD所以AOE=EOD=AOD/2=30度
互余的角:∠BOE和∠DOC ∠BOE和∠AOC  
∵∠AOC=58°,OC平分∠AOD∴∠AOD=2∠AOC=116°∵∠AOD与∠BOD互补∴∠AOD+∠BOD=180°∴∠BOD=64°∵OE平分∠BOD∴∠BOE=1/2∠BOD=32°
∵OE平分∠BOD∴∠DOE=1/2∠BOD∵OC平分∠AOD∴∠COD=1/2∠AOD∴∠COE=1/2(∠AOD+∠BOD)=1/2*78=39°
22.5°再问:麻烦您说下过程!谢谢!再答:∠DOE=0.5∠AOD∠DOF=0.5∠BOD∠EOF=∠DOE+∠DOF=0.5∠AOD+0.5∠BOD=0.5∠AOB=22.5°
角BOC=角BOD-30角BOC+角BOD=180得角BOC=75角BOD=105角BOC=角AOD=75OE平分角AOD角COE=角COA+1/2角AOD=角BOD+1/2角AOD=105+37.5
OE评分角BOD,∠AOD︰∠BOE=7︰1∠AOD︰∠BOD=7︰2∠AOD+∠BOD=180º∠AOD=180º×7/(7+2)=140º,∠BOD=60º
∵∠AOD+∠BOO=180°∠AOD-∠BOC=30°∴∠AOD=105°∠BOD=75°∵∠AOC与∠BOD对顶角∴∠AOC=∠BOD=75°∵OE平分∠AOC∴∠AOE=∠COE=37.5°∴∠
角AOC=角AOD-80所以角AOD-角AOC=80,又因为角AOC加上角AOD等于180,所以能求出角AOD=130角AOC等于50度.又因为角AOC和角DOB是对等角,所以角DOB也等于50度OE
∵oc平分∠AOD∴∠DOC=∠AOC∵OE平分∠BOD∴∠BOE=∠EOD∵∠EOC=∠DOE+∠DOC∴∠AOB=∠BOD+∠DOA=2∠DOE+2∠DOC=2(∠DOE+∠DOC)=2∠EOC=
设角AOD为X,角DOB为Y有X+Y=180X-Y=80解得X=130Y=50角AOC和角DOB所以角AOC为50度角DOE为25度
∠BOD+∠AOD=180°所以1/2×∠BOD+1/2×∠AOD=90°因为OC,OE分别是∠BOD和∠AOD的角分线所以∠COD=1/2×∠BOD,∠EOD=1/2×∠AOD因为∠COD+∠EOD