设a为锐角,若cos(a π 6)=4 5,则

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求正确答案和解析.已知A为锐角,且2tan(π-A)-3cos(π/2+B)+5=0,tan(π+A)+6sin(π+B

答案:3√10/10分析:先根据诱导公式进行化简整理,然后求出tanA,最后根据同角三角函数关系求出sinA即可.∵2tan(π-A)-3cos(π/2+B)+5=0,tan(π+A)+6sin(π+

设向量a=(cosα,cosβ),b=(cosθ,cosφ),c=a+tb,(t属于R)其中αβθφ均为锐角且α+β=θ

α+β=θ+φ=π/2所以有cosβ=sin(π/2-β)=sinα,cosθ=sin(π/2-θ)=sinφa*b=cosα*cosθ+cosβ*cosφ=cosα*sinφ+sinα*cosφ=s

设向量a=(cosa,sina),b=〔sin(π/4-a),cos(π/4-a)〕,c=a+tb,其中a为锐角

是关于三角函数的化简啊1)a*b=cosa*sin(π/4-a)+sina*cos(π/4-a)=sin(π/4)=根2/22)最小值的求是:|c|*|c|=|a|*|a|+2ab+|b|*|b|=1

、设a为锐角,若cos(a+pi/6)=4/5,则sin(2a+pi/12)的值为?

a为锐角,cos(a+π/6)=4/5所以,sin(a+π/6)=3/5sin(2a+π/3)=2sin(a+π/6)cos(a+π/6)=2×(3/5)×(4/5)=24/25cos(2a+π/3)

设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)的值为多少?

设b=a+π/6,sinb=3/5,sin2b=2sinbcosb=24/25,cos2b=7/25sin(2a+π/12)=sin(2a+π/3-π/4)=sin(2b-π/4)=sin2bcosπ

设a为锐角,若cos(a+pi/6)=4/5,则sin(2a+pi/12)的值为?

cos(2a+π/3)=2cos²(a+π/6)-1=7/25a为锐角,则:2a+π/3∈(π/3,π/2)∴sin(2a+π/3)=24/25sin(2a+π/12)=sin[(2a+π/

设a为锐角,若cos(a+π/6)=3/5,则sin(a–π/12)的值为?

a为锐角,cos(a+π/6)=3/5则:sin(a+π/6)=4/5sin(a-π/12)=sin[(a+π/6)-π/4]=sin(a+π/6)cos(π/4)-cos(a+π/6)sin(π/4

设a为锐角,若cos(a+π/6)=4/5,则sin(2a+π/12)值为

sin(2a+π/12)=sin【2(a+π/6)—π/4】=sin2(a+π/6)cos(π/4)—cos2(a+π/6)sin(π/4)因为cos(a+π/6)=4/5,a为锐角,所以0

设A为锐角 若cos(A+π/6)=0.8,则sin(2A+π/12)=?

设A+π/6=α,则2A+π/12=2α-π/4cosα=4/5,α为锐角,sinα=3/5,所以sin2α=2sinαcosα=24/25,cos2α=2(cosα)^2-1=7/25sin(2A+

设a为锐角,若cos(a+6分之拍)=5分之3,则sin(a-12分之拍)=?

a为锐角,cos(a+π/6)=3/5则:sin(a+π/6)=4/5sin(a-π/12)=sin[(a+π/6)-π/4]=sin(a+π/6)cos(π/4)-cos(a+π/6)sin(π/4

设α为锐角,若cos(α+π/6)=4/5,求sin(2α+π/12),

设α为锐角,若cos(α+π/6)=4/5,求sin(2α+π/12),cos(α+π/6)=4/5sin(α+π/6)=3/5,sin(2α+π/3)=24/25cos(2α+π/3)=7/25si

设向量a=(3,sinα)b=(√3,cosα)且a//b则锐角α为

a//b,可得:a=tb,所以有:3=√3t解得:t=√3sina=cosat所以:sina/cosa=t即:tana=√3 得:a=60°

已知a为锐角且cos(a+π/6)=4/5则cosa的值为

本题可以利用角的变换技穷,直接解方程比较麻烦.a是锐角则0

设a是锐角,若2*sin a*cos a+1/3*sin a-1/3*cos a=1,求tan a*cot a 为根的一

设sina-cosa=t则2sinacosa=1-t^21-t^2+(1/3)t=13t^2-t=0t=0或t=1/3sinacosa=1/2或4/9tana+cota=1/sinacosa=9/4t

若a为锐角,cos(a+30)=4/5,则sin(2a+15)=

a∈(0,90)a+30∈(30,120)sin(a+30)>0sin(a+30)=3/5sin(2a+60)=2sin(a+30)cos(a+30)=24/25又cos(a+30)>cos45,a+