计算x的平方 6x 9分之x-3
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/09 16:07:58
x^2/(x-3)-(2x-3)/(3-x)+(2x+6)/(3-x)=x^2/(x-3)+(2x-3)/(x-3)-(2x+6)/(x-3)=[x^2+(2x-3)-(2x+6)]/(x-3)=(x
原式=[(x²+2x)/(x²+4x+4)]÷[(2x²-8)/(3x+6)]÷[1/(x²-4)]=[x(x+2)/(x+2)²]÷{2(x+2)(
x/(x²-3x)×(x²-9)=x/x(x-3)×(x-3)(x+3)=x+3
是求X的值吗?不晓得对不对哈,姑且一看吧 由已知可得:
x的平方-9分之1-x-3分之1除以x-1分之6+2x=1/(x^2-9)-1/(x-3)*(x-1)/2(3+x)=(2-(x-1))/2(x^2-9)=(3-x)/2(x^2-9)=-(x-3)/
你要求的是不是((2x-6)/(x^2-4x+4))*(2x-4)/(x-3),如果是,((2x-6)/(x^2-4x+4))*(2x-4)/(x-3)=(2(x-3)/(x-2)^2)*2(x-2)
)【(x²-2x+1)/(x²-1)】÷【(x-1)/(x²+x)】=【(x-1)²/(x+1)(x-1)】÷【(x-1)/x(x+1)】=【(x-1)/(x+
[(x的平方-3x)分之(x+3)-(x的平方-6x+9)分之(x-1)]÷x分之(x-9)=[(x+3)/(x^2-3x)-(x-1)/(x^2-6x+9)])]÷[(x-9)/x]=[(x+3)/
x的平方-2x+1分之x-3÷x-1分之x的平方-9=[(x-3)/(x-1)²]*[(x-1)/(x+3)*(x-3)]=1/(x-1)(x+3)
请核对题目是不是多写了y²x²-5x+6分之x²-3x+2的平方/x²-2x-3分之x-1的平方=[(x²-3x+2)/(x²-5x+6)]
=3/2(x+2)+6/(x²-4)+9/2(x-2)=3(x-2)/[2(x+2)(x-2)]+12/[2(x+2)(x-2)]+9(x+2)/[2(x+2)(x-2)]=(3x-6+12
(x²+6x+9)分之(x-3)+(9-x²)分之x=(x²+6x+9)分之(x-3)-(x²-9)分之x=(x+3)²分之(x-3)-[(x+3)(
(8x^2/9y^2)*(3y/-4x)=-2x/3y不懂请追问,满意请采纳~再问:过程????再答:就相当于(8x的平方除以-4x)乘以(3y除以9y的平方)=-2x乘以3y分之一=负的3y分之2x
[(x-2)分之3x-2分之x]×x分之(x²-4)=[2(x-2)分之6x-2(x-2)分之(x²-2x)]×x分之[(x+2)(x-2)]=2(x-2)分之(4x-x²
x分之x-3*9-x的平方分之x=(x-3)/x*x/(3-x)(3+x)=-(x+3)=-x-3
原式=1/(x-3)-1/2(x+3)-x/(x-3)²=[2(x+3)(x-3)-(x-3)²-2x(x+3)]/[2(x+3)(x-3)²]=(2x²-18
(x的平方-16)分之(6-5x+x的平方)÷(4-x)分之(x-3)×(4-x的平方)分之(x的平方+5x+4)=(x^2-5X+6)/(X^2-16)×(4-X)/(X-3)×(X^2+5X+4)
=7x²-4/9x+1再问:?过程再答:你能把我的式子复制下再输入一下原题吗再问:=7x²-4/9x+1;{4(x)的平方-(9分之4x)+1}{-3(x)的平方}再答:哦,是(4