计算1~100之间的所有7的倍数之和. **输出格式要求:sum=%dn-搜答案-智慧作业帮

你一点都不做?做一做大家给你修改才是正途

witht(n)as(select1unionallselectn+1fromtwheren

PublicSubqqqqq()DimiAsIntegerDimjAsIntegerDimsAsIntegerDimCAsBooleans=0Fori=2To100C=FalseForj=2Toi-1

dimiaslongdimsumaslongsum=0fori=1to100step2sum=sum+inextiprintsum

1、clears=0fori=1to100ifi%3=0s=s+iendifendfor"1~100之间所有3的倍数之和：",s2、值太大,计算不出结果3、clears=0fori=1to100s=s

Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+iEndIfNext==>优化一点：Sum=0Fori=100To300IfiMod21=0ThenSum=Sum+ii

#includeintmain(void){inti,sum;sum=0;for(i=1;i

设置了没5个换行PrivateSubBcompute_Click()t=0Fori=1To12260If(iMod3=0)And(iMod7=0)And(iMod9=0)ThenTresult.Tex

declare@iint,@Jsumint,@Osumintset@i=1set@Jsum=0set@Osum=0while(@i

#includevoidmain(){intsum=0,i;intoushu=0,jishu=0;for(i=0;i

SETTALKOFF**关掉人机对话,就是屏幕不显示运行结果N=2**赋值语句S=0**赋值语句DOWHILEN

1+3+...+99=(1+99)*50/2=2500

publicclassSumOfEven{\x09publicstaticvoidmain(String[]args){\x09\x09intsum=0;\x09\x09for(inti=1;i

#includevoidmain(){inti;intsum=0;for(i=1;i

a=0'和的变量fori=0to100ifimod70thena=a+i'如果不能被7整除,就是除7的余数不等于0的话,累加起来nextimsgboxa再问：是要这样的窗体。。再答：学程序的人没有人会

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e&

subbeisu()dimbeisu3asintegerdimbeixu7asintegerbeisu3=0beisu7=0fori=1to1000ifimod3=0thenbeisu3=beisu3

//分别计算1到1000之间所有3的倍数之和和所有7的倍数之和intmain(){intsumA=0;//3的倍数的和intsumB=0;//7的倍数的和for(inti=1;i

n=3s=0dowhilen

dimiasintegerdimaasintegera=3*7*9fori=1to13230ifimoda=0then'这里你要对i干什么?,我就打印到立即窗口上debug.printiendifne