要求输入十个整数,统计其中偶数的个数

#includemain(){intt,i,c0=0,c1=0,c2=0;for(i=0;i

如果觉得好,#includevoidmain(){inta[10],i;intpositive_num,negative_num,zero_num;positive_num=negative_num=

#includevoidmain(){inta[10],i,sum=0,count=0;printf("请输入10个整数：\n");for(i=0;i再问：奇数输出不了 再答：不好意思，我是

#includeusingnamespacestd;voidmain(){cout

#include "stdio.h"int main(){   int count1=0,count2=0,i;&nbs

vari,k,n1,n2:integer;beginn1:=0;n2:=0;fori:=1to20dobeginreadln(k);ifk>0thenn1:=n1+1elseifk

#includevoidmain(){inta[10];inti,n=0;floatsum=0;for(i=0;i

#includevoidmain(){inta[10],i,s=0,n=0;for(i=0;i再问：有3错误啊再答：你是在什么环境下编译的？我是在VC++6.0编译的，没问题。你把10改成100就行了

PrivateSubCommand1_Click()Dima(1To20)AsIntegerDimiAsInteger,t1AsInteger,t2AsIntegerFori=1To20a(i)=In

楼上的,100个数#includemain(){intj=0,k=0,l=0;int*p;inta[100];for(p=a;p

vara,n,i:longint;beginfori:=1to10dobeginread(a);ifa>0thenn:=n+1;end;write(n);end.

//#includeintmain(){inti,a[4]={0},b[10];for(i=0;i{scanf("%d",&b[i]);if(b[i]>0)//正数累加和a[0]+=b[i];else

intmain(){inta[9],i,j,*temp1,*temp2;//temp1指向表示最小数,temp2指向表示最大数for(i=0;i再问：开始应定义a[10]；这样写a[0]=*temp1

#includevoidmain(){inti,a,b,c,t;a=b=c=0;for(i=0;i0)a++;if(t==0)b++;if(t

C++的：#includeusingnamespacestd;intmain(){cout

if(x%5==0){g=g+1;sum3=sum3+x;}}}//下面的大括号拿到这里printf("奇数之和为%d\n",sum1);printf("偶数之和为%d\n",sum2);printf

#includevoidmain(){inti,n,count=0;for(i=0;i=0)count++;}printf("正数的个数为:%d\n",count);printf("负数

#includeintmain(){int*p,*q;intmax=0,min=100;p=&max;//指针P指向maxq=&min;//指针q指向minintx;scanf("%d",&x);wh

inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=

#include#include#defineMAX1000intmain(){inta[MAX],i,j,n,p,q,s1,s2;p=0;q=0;s1=0;s2=0;printf("请输入要输入的值