((3x-2)的平方的等于0怎么因式分解
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由x²-3x+2=0可得x=2或x=16x-(2x)²=x(6-2x)当x=2,x(6-2x)=2×(6-2×2)=4或x=1,x(6-2x)=1×(6-2×1)=4所以6x-(2
答:3x^2-2x=0(3x-2)x=0x1=0,x2=2/3
再问:负2分之3绝对值减(负2011)0次方加4除(负2)3次方再问:能快点吗。再问:拜托了
原式=(x^2-3-2x)(x^2-3+x)=(x-3)(x+1)(x^2+x-3).
2x^2-6x+1=02(x^2-3x)+1=0x^2-3x=-1/26+3x-x^2=6+1/2=13/2
3X^2-X-2=0X^2-2*(X/6)+1/36=1/36+2/3=25/36(X-1/6)^2=25/36解的:X-1/6=5/6或X-1/6=-5/6可得:X=1或X=-4/6
-X-2X+3≥0-3X≥-3X≤1解集为:-1≤X≤1
x的平方-3x+2等于0(x-1)(x-2)=0x=1或x=21.x=16x-2x^2=42.x=26x-2x^2=12-8=4
=∫-x²/5x²dx=∫(-1/5)dx=-x/5+C=∫9^x*e^xdx=∫(9e)^xdx=1/ln(9e)*∫ln(9e)*(9e)^xdx=(9e)^x/ln(9e)+
3x^2=2x3x^2-2x=0x(3x-2)=0x=0,x=2/3
再问:谢谢了
(x-3)²+4x(x-3)=0(x-3)[(x-3)+4x]=0(x-3)(5x-3)=0x1=3,x2=3/59(x-2)²=4(x+1)²3(x-2)=2(x+1)
3x^2=2x3x^2-2x=0x(3x-2)=0x1=0,x2=2/3
解(2x-3)^2=x^24x^2-12x+9=x^23x^2-12x+9=0x^2-4x+3=0(x-1)(x-3)=0x=1或x=3
X的平方减3X减2等于0?求根公式x=3正负根号(9+8)/2=(3±根号17)/2施主,我看你骨骼清奇,器宇轩昂,且有慧根,乃是万中无一的武林奇才.潜心修习,将来必成大器,鄙人有个小小的考验请点击在
∵2(x+y)²-3x-3y-2=02(x+y)²-3(x+y)-2=0[(2(x+y)+1][(x+y)-2]=02(x+y)=-1或(x+y)=2即:x+y=-1/2或x+y=
(3+/-2倍根号5)/3