若x²-4x+y²+2y

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x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2

写清楚点点比如说前面是X/X还是X/(X-Y)打上括号分段这样才能清楚的做

若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值?

(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)=4x^2-y^2+2xy-8x^2-y^2+4xy+2y^2-6xy=-4x^2=-4(-1/4)^2=-1/4

若3x-4y=0,则x/y=______,(x-y)/y=______,(3x+2y)/(2x+3y)=_____.

3x=4Y.X/Y=4/3,x-y)/y=(X/Y)-1=1/3,(3x+2y)/(2x+3y)=(4Y+2y)/(8/3y+3y)=18/17(因为3x=4Y,2x=8/3y)再问:若3X-4Y=0

计算若(3x+2y)(2x+3y)-(x-3y)(3x+4y)

(3x+2y)*(2x+3y)-(x-3y)*(3x+4y)=6x^2+13xy+6y^2-3x^2+5xy+12y^2=3x^2+18xy+18y^2

{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y

(x-y)(z+y-x+y+2y)÷4y=(x-y)(z-x+4y)÷4y{(x+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y=(x-y)(x+y-x+y+2y)÷4y=(x-y)(4

(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)

(2x+y)(2x-3y)+x(2y+y)=(2y+y)(2x-3y+x)=(2y+y)(3x-3y)=3(2y+y)(x-y)2a(x-y)-4b(x-y)=2(x-y)(a-2b)

x^2-y^2/x+y-4x(x-y)+y^2/2x-y,

(x^2-y^2)/(x+y)-(4x(x-y)+y^2)/(2x-y)=(x-y)(x+y)/(x+y)-(4x^2-4xy+y^2)/(2x-y)=(x-y)-(2x-y)^2/(2x-y)=(x

若|x+y+4|=-(x-y)4次方,则(-2y)平方x=

根据绝对值和完全平方数的意义,两个只能是都为0.所以x+y+4=0x-y=0x=y=-2(-2y)*x^2=16

若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*

(x*x+y*y)(x*x+y*y)-4x*x*y*y=(x^4-2x^2y^2+y^4)=(x^2-y^2)^2=0x^2=y^2x/y=±1(x*x+5xy+y*y)/(x*x+2xy+y*y)=

若5x+3y=3x+4y=x+2y+6,则x+y=___

3x+4y=x+2y+62x-x+4y-2y=62x+2y=6x+y=6/2x+y=3

若X,Y是整数,求证:(x+y)(x+2y)(x+3y)(x+4y)+y的四次方是一个完全平方数

(x+y)(x+2y)(x+3y)(x+4y)+y^4=[(x+y)(x+4y)][(x+2y)(x+3y)]+y^4=[(x^2+5xy)+4y^2][(x^2+5xy)+6y^2]+y^4=(x^

(2x-y)^2-4(x-y)(x+2y)

4x^2+y^2-4xy-4(x^2-xy+2xy-2y^2)展开化简吧!

4x(y-x)-y^2因式分解

4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点

1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y

1)(2x+5y)(2x-5y)(-4x^2-25y^2)=-(4x^2-25y^2)(4x^2+25y^2)=-(16x^4-625y^4)=625y^4-16x^42)[(x+y)(x-y)-(x

若X=负四分之一,能否确定代数式(2X-Y)(2X+Y)+(2X-Y)(Y-4X)+2Y(Y-3X)的值?

先化简原式=(2X-Y)(2X+Y)+(2X-Y)(Y-4X)+2Y(Y-3X)=4x"2-y"2-8x"2-y"2+6xy+2y"2-6xy=-4x"2=-1/4可以确定上式得值

化简:(2x-y)²-4(x-y)(x+y)

(2x-y)²-4(x-y)(x+y)=(4x²-4xy+y²)-4(x²-y²)=4x²-4xy+y²-4x²+4y&

x+2y+4y^2/x-y+4x^y/4y^2-x^2

“4y^2/x-y”应该是“4y^2/x-2y”吧x+2y+4y^2/x-2y+4x^2y/4y^2-x^2=(x+2y)+4y^2/(x-2y)+4x^2y/(2y-x)(2y+x)=(x+2y)+

若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&

∵|x+2y-1|+y²+4y+4=0∴|x+2y-1|+(y+2)²=0∴x=5,y=-2(2x-y)²-2(2x-y)(x+2y)+(x+2y)²=[(2x

(x+3y-4)(2x-y)

原式等于2x^2-xy+6xy-3y^2-8x+4y=2x^2+5xy-3y^2-8x+4y