若2x-y的平方=4x的平方+kxy+y的平方
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x^2-y^2=(x+y)(x-y)30=4/3*(x-y)x-y=30*3/4x-y=45/2
原式=(2x-y)(2x+y)(4x^2+y^2)=(4x^2-y^2)(4x^2+y^2)=16x^4-y^4
(1)x的平方-y的平方+4x+4y=(x+y)(x-y)+4(x+y)=(x+y)(x-y+4)(2)x的平方*y的平方+1-x的平方-y的平方=x²y²-x²+1-y
若y=根号[(x^2-2)/(5x-4)]+[根号(x^2-2)/(4-5x)]+2[(x^2-2)/(5x-4)]>=0(x^2-2)/(4-5x)]>=0两个相反数同时大于或等于0,两个必须都为0
原式=(x²+y²+2xy)(x²+y²-2xy)/(x+y)²=(x+y)²(x-y)²/(x+y)²=(x-y)
即(x²+2x+1)+(4y²-4y+1)=0(x+1)²+(2y-1)²=0平方相加为0则都等于0所以x+1=0,2y-1=0x=-1,y=1/2所以5x&s
4/x-15x²y再问:朋友,发一下过程再答:3x²y-(-3x)²×(2y)+x³y²/(x²x²y²/4)=3x
x²-4x+y²-10y+29=0x²-4x+4+y²-10y+25=0(x-2)²+(y-5)²=0∵(x-2)²≥0,(y-5
原式=9x⁴/16y²*2y/3x+x²/2y²*x/2y²=3x³/8y+x³/4y⁴=(3x³y
(x+2y)的平方-4x的平方=(x+2y+2x)(x+2y-2x)=(3x+2y)(2y-x)
x^2-2x+y^2-4y+5=0,所以:(x-1)^2+(y-2)^2=0所以:x-1=0,y-2=0,解得:x=1,y=2所以:9x^2y^2-12x^3y^2+4x^4y^2=9y^2-12y^
x的平方乘y的平方-4-2x的平方乘y的平方=-x的平方乘y的平方-4
(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!
得1将x^2+y^2看为一个整体,变为一个二次方程,解得1和-4,-4舍去.再问:������������£���������ô���ġ�再答:���[http://pinyin.cn/1tSiLPG
x8+256y8-32x4y4(用手机打的不要介意,给个最佳答案吧)
由题意可得:(2xy-y²)/(x²-y²)+(x-y)/(x+y)=[(2xy-y²)+(x-y)²]/(x²-y²)=x
(x的平方-4Y的平方)-(x+2y)²=(x+2y)(x-2y)-(x+2y)²=(x+2y)(x-2y-x-2y)=-4y(x+2y)(x的平方-y的平方)(x+y)-(x-y
ax^2+3x^2+4x-1-2(x^2-y+2x)=ax^2+3x^2+4x-1-2x^2+2y-4x=(a+1)x^2+2y-1a+1=0a=-1a^2=1
x的平方-x-4y的平方+2y=(x-2y)(x+2y)-(x-2y)=(x-2y)(x+2y-1)
x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²