若2x-3Y-1=0,求10的2x次方初一10的3Y次方的值

0的0次幂无意义y=5,x=0

2x-3y=0(1)3x-y-1=0(2)由（2）得y=3x-1(3)把y=3x-1代入(1)得2x-9x+3=0∴x=3/7把x=3/7代入（3）得y=2/7∴x=3/7y=2/7

|x-1|+2(y+3)^2=0所以x-1=0,y+3=0x=1,y=-3x+y=-2

实数x,y满足(x-y-5)的平方+/2x+3y+20/=0x-y-5=0(1),2x+3y+20=0(2)由（1）+（2）得3x+2y+15=03x+2y+1=-14

3(1/x+1/y)=(x+2y)(1/x+1/y)=1+x/y+2y/x+2=3+(x/y+2y/x)x/y>0,2y/x>0所以x/y+2y/x≥2√(x/y*2y/x)=2√2所以3(1/x+1

(3x+2y-10)^0无意义∴3x+2y-10=0①2x+y=5②2②-①得：x+10=10,x=0y=5明教为您解答,请点击[满意答案];如若您有不满意之处,请指出,我一定改正!希望还您一个正确答

（x+y+1）的平方+|x-y+2|=0所以x+y+1=0,x-y+2=0所以x+y=-1x-y=-2所以原式=-6(x+y)²-13(x-y)=-6+26=20再问：谢谢，似乎还有一种方法

若（y-5）^0=1无意义,所以y-5=0y=5又3x+2y=10所以3x+10=10x=0所以x*y=0

/>（x+y+3）(x-y-2)=0x,y互为相反数则x+y=0...(1)带入上式3（x-y-2）=0x-y=2...(2)联立（1）（2）得x=1,y=-1

-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}=-6x+3y-7x+(6x+2y-10x+8y)+x+6x-8y=-13x+3y-4x+10y+7x-8y=-10x

x^5+x^4y+x^4+x+y+1=0x^4(x+y+1)+x+y+1=0(x^4+1)(x+y+1)=0然后因为x^4+1不可能等于0所以只有x+y+1=0x+y+1=03x+2y=1这两个公式,

x^2+2x+y^2-6y+10=x^2+2x+1+y^2-6y+9=(x+1)^2+(y-3)^2=0得出x=-1y=3所以x^3y=-3

x+y=1x-y=2(x+2y)(x-2y)-(2x-y)(-y-2x)=(x+2y)(x-2y)+(2x-y)(y+2x)=x²-4y²+4x²-y²=5x&

x+2y=1+m2x+y=3先解方程组,将前面的式子,成与22x+4y=2+2m2x+y=3两式相减,3y=2m-1同理后面的式子成2x+2y=1+m4x+2y=6两式相减,3x=5-m将得到的式子相

7y(x-3y)²-2(3y-x)³=7y(x-3y)²+2(x-3y)³=(x-3y)²[7y+2(x-3y)=(x-3y)²(7y+2X

x^2+y^2-8x-10y+41=0x^2-8x+16+y^2-10y+25=0(x-4)^2+(y-5)^2=0所以x=4,y=5x/y+y/x＝4/5+5/4=0.8+1.25=2.05

(1)x²+y²-4x+10y+29=0(x-2)²+(y-5)²=0∴x-2=0,y-2=0∴x=2.y=2(2)题目打错了吧.应该是（2x-3)²

因为绝对值大于等于0y+5=0y=-5x-2=0x=2-6x+3y-(6x+2y-10x+8y)=-6x+3y-(10y-4x)=-6x+3y-10y+4x=-2x-7y将x=2y=-5代入=-4+3

答：x^2-3x+1=0y^2-3y+1=0所以：x和y是方程a^2-3a+1=0的两个根根据韦达定理：x+y=3xy=1所以：(x+y)^2=9x^2+2xy+y^2=9所以：x^2+y^2=7所以