12-2x=7,6解方程

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解方程:(x+3)/(x+2)-(x+5)/(x+4)=(x+7)/(x+6)-(x+9)/(x+8)

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么

解方程(x-2)/(x-3)-(x-3)/(x-4)=(x-5)/(x-6)-(x-6)/(x-7)

((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30

解方程:x^2-7x-12=0

x²-7x=12x²-7x+49/4=12+49/4(x-7/2)²=97/4x-7/2=±√97/2x=(7-√97)/2,x=(7+√97)/2

解方程(x+1/x+2)-(x+2/x+3)=(x+5/x+6)-(x+6/x+7)

我给个思路吧(X+2-1/X+2)-(X+3-1/X+3)=(X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决

解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)5x/(x-2)(x+3)+(2x-5)/(x+3)(x-4)=(7x-10)

方程2/x+6/x+12/x+```+2008*2009/x=2008 的解x=

提出x得到:x*(1-1/2+1/2-1/3+1/3-1/4……+1/2008-1/2009)=2008接着:x*(1-1/2009)=2008最后:x=2009

解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得

(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)(5-2x)/(x-4)(x+3)=5x/(x+3)(x-2)+(10-7x)/(x-2)(x-4)分

7x(x-6)+3x=4x(2x+5)怎么解这个方程

 再问:2x是怎么得来的

解方程2x^2-5x-7x-2x^2+12,其中x=1/6

2x^2约掉剩下-12X+12再把X=1/6代入得10再问:我少写了一个负号,应该是2x^2-5x-7x-2x^2+12,其中x=-1/6再答:那就代X=-1/6前面不变,答案为14

解分式方程,7/(x^2+x)+3/(x^2-x)=6/(x^2-1)

7/(x^2+x)+3/(x^2-x)=6/(x^2-1)7/x(x+1)+3/x(x-1)=6/(x-1)(x+1)分子分母同乘以x(x-1)(x+1),得7(x-1)+3(x+1)=6x10x-4

解方程:x+2/x+1-x+3/x+2=x+6/x+5-x+7/x+6

通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2

解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

6 x=7(x-12)解方程

6X=7(X-12)6X=7X-847X-6X=84X=84

解方程:6-x=2x

2再问:过程再答: 

解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8

5x/(x²+x-6)+(2x-5)/(x²-x-12)=(7x-10)/(x²-6x+8)5x/[(x+3)(x-2)]+(2x-5)/[(x-4)(x+3)]=(7x

2x+7x+2.1=12,解方程

9x+2.1=12,9x=12-2.1,9x=9.9,x=1.1

7x=6x+12解方程

移项,得x=12再问:过程再答:7x=6x+127x-6x=12x=12

解方程:x/2+x/6+x/12+x/20+x/30=5

你懒惰了,通分得:50x=300x=6

解方程:x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)1+2/(x-2)+1-2/(x-7)=1+2/(x-1)+1-2/(x-6)1/(x-2)-1/(x-7)=1/