编程输出Fibonacci数列1,1,2,的前二十个数每行输出四个
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#includeintmain(){intf1=1,f2=1;inti;for(i=1;i
#includeusingnamespacestd;intmain(){inta,b,i;a=1;print("%d\n",a);for(i=0;i
#includeintFibonacci(intn){if(n==0)return1;elseif(n==1)return1;elsereturnFibonacci(n-2)+Fibonacci(n-
#includevoidmain(){inta[40],i;a[0]=a[1]=1;for(i=2;i
PrivateSubForm_Click()DimnAsIntegern=Val(InputBox("请输入N:"))Dima,bAsLonga=1:b=1Fori=1TonPrinta&""&b&"
#include#include#includeusingnamespacestd;#defineM100inta[M];voidmain(){inti,j;a[0]=1;a[1]=2;i=1;
OptionExplicitDimf(40)AsLongPrivateSubCommand1_Click()DimiAsByteDimsAsLongf(1)=1f(2)=1s=2Print"No1:"
inta[101],i;a[0]=0,a[1]=1;floatt;for(i=2;i
#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)
这是数学题?!确定不是程序设计...1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,搞定,希望没算错...其实斐波
#includeusingnamespacestd;intmain(){intf[11]={0,1,1};inti,j,n;for(i=3;i{f[i]=f[i-1]+f[i-2];i
#includeusingnamespacestd;intmain(){ints=1,a=1,t=0,i=0;cout再问:改完后问什么提示我cannotopendebugexeforwriting谢
#includevoidmain(){longf1=1,f2=1,i;for(i=0;i
Private Sub Form_Load()Dim I As IntegerForm1.AutoRedraw = TrueFor
我给你代码:#include <stdio.h>#include <stdlib.h>#define N 47int fibo
vari,j,k,n:integer;begini:=1;j:=1;write(i,',',j);n:=2;repeatk:=i+j;i:=j;j:=k;write(',',j);inc(n);unt
publicclassTest{publicstaticintfib(intn){if(n==1||n==2)return1;elsereturnfib(n-1)+fib(n-2);}publicst
publicclassFibonacci1{publicstaticlongfib(intn){longf1=1,f2=1;longm=0;if(n
#includevoidmain(){inta[20];int*p=a;*p=0;*(p+1)=1;for(inti=2;i
下面的程序可以修改宏定义N的值来确定输出的数的个数#include#defineN30voidmain(){unsignedlonginta[N];inti,j;a[0]=1;a[1]=1;for(i