编程给定任意数字,分别打印出其各个位上的数用sublime

/*c语言编程 给定一个自然数N（1≤N≤1000）,统计出所有不超过N的正整数中数字0到9出现的次数,并且依次打印出来每个数字出现的次数（0～9）,相邻两个数字用一个空间隔开.输入输出样立

#include"stdio.h"#defineN5voidmain(){inti,j;for(i=0;i

intmain(void){\x05intn;\x05intcount=0;\x05inta,b,c,d,e;\x05printf("请输入一个不低於5位的正整数：");\x05scanf("%d",

#includevoidmain(){charline[30];inti,count1=0,count2=0,count3=0,count4=0;printf("\n请输入一行字符:");gets(l

#include"stdio.h"voidmain(){unsignedlonginta=0;//用int可能会溢出//intflag=0;intb[5];//以下部分用于判断数据的位数//while

cin>>x;inta=x/100,b=x/10%10,c=x%10;cout

publicstaticvoidmain(String[]args){//TODOAuto-generatedmethodstubScannerinput=newScanner(System.

#include#includevoidmian(){intnum,i,temp[5];printf("请输入一个低于5位的整数\n");scanf("%d",&num);for(i=0;i

#includeintmain(void){longintx;inty,i=1;printf("请输入一个不超过100000的整数:");//99999||x

charsNum[8];intnumber=0;intnCount=0;cin>>number;charstring[25];memset(string,0,25);itoa(number,strin

#include<stdio.h>int arr[10] = {0,1,2,3,4,5,6,7,8,9};int main(){ &nbs

#includemain(){longm,a,b,c,d,e;printf("请输入一个整数:(0~99999):\n");scanf("%ld",&m);e=m%10;d=m/10%10;c=m/1

#includevoidmain(){inta,b,c,d,e;unsignedinti;//定义i位无符号的整型变量printf("pleaseenterthenumber:\n");scanf("

packagecomm.db2;/***@authorjifei**/publicclassOrder{Stringstr1="";inttempi=0;publicOrder(){}publicOr

1、clears=0m=1fori=1to10input"请输入一个数："toaifa/2=int(a/2)s=s+aelsem=m*aendifendfor?"奇数的积是：",m?"偶数的和是：",

#includevoidmain(){intnum;printf("输入一个3位数:\n");scanf("%d",&num);printf("个位:%d\n十位:%d\n百位:%d\n",num%1

#include#include#defineN9//范围可以是1到9intmain(){constchar*str="";intnum[20];inti;for(i=1;i

#includeintmain(){inti,j,k=1,temp;printf("pleaseinputyourlayer:");scanf("%d",&temp);if(temp>10)

static void Main(string[] args){   Console.WriteLine(resultJT(0, 

intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(