编程求出个位数是6

dimii=0forj=100to999ifjmod3=0thenif(j-6)mod10=0theni=i+1endifendifnext没有编译运行LZ自己试试

#includevoidmain(){intx,i=0;for(x=106;x

intn=0,i=1000;for(i=1000;i9){printf("\n");n=0;}}}}测试通过,绝对没错.

PrivateSubCommand1_Click()Fori=100To999IfMid(i,2,1)Mod2=0AndMid(i,3,1)Mod3=0AndMid(i,3,1)Mod6=0ThenP

Function Exchange(ByVal num As Integer)    If num 

#include#includeintmain(){intn,m,i,count=0;scanf("%d%d",&n,&m);for(i=pow(10,n)+6;i再问：呃，输入23输出是30诶。。再

#inclludemain(){inta[]={3,1,5,9,6,2};inti.j,max,sum=0;max=a[0];for(i=0;imax)max=a[i];sum+=a[i];}prin

#includemain(){inti;for(i=1;i

PrivateSubCommand1_Click()Dimi,j,a,b,sFori=7To997a=FalseForj=1Toi-1IfiModj=0Andj>1Thena=TrueExitForE

#includeintmain(){inti=0,sum=0,count=0;//i循环,sum和,count个数for(i=10;i

#includevoidmain(){\x05intodd=0;//奇数\x05inteven=0;//偶数\x05doubleodd_sum=0;//奇数总和\x05doubleeven_sum=0

intpingfang(inti){intm;m=i*i;returnm;}intlifang(intj){intn;n=j*j*j;returnn;}

main(){inti=3;while((i+3)%5!=0||(i-3)%6!=0)i++;printf("%d\n",i);}运行结果是：2727+3＝30,是5的6倍27-3＝24,是6的4倍

intn=0;for(inti=1;i再问：对，就是这样的再答：那你运行下看程序行不行再问：行的～谢谢

PrivateSubCommand1_Click()DimgAsInteger,sAsInteger,bAsInteger,nAsInteger,iAsIntegerFori=100To999g=Mi

时间有限,只写了C++代码,未调试,思路相同,自己切换吧#include"math.h"BOOLIsPrime(inta){inti;for(i=2;i再问：非常感谢～

输出100以内能被7整除且个位数是4的所有整数c++编程题#includeusingnamespacestd;intmain(){inti;for(i=1;i

//输出100以内能被3整除且个位是6的元素#includevoidmain(){inti,j;for(i=0;i

设十位为X,个位为YX+Y=9(10Y+X)-(10X+Y)=9解得X=4Y=5故原来两位数为45

设个位数为X,十位数为（X+6）,这个两位数[10（X+6）+X].31X=10(X+6)+X31X=10X+60+X31X-10X-X=6020X=60X=3两位数=3×31=93答：这个两位数是9