编程实现求100到1000的素数-搜答案-智慧作业帮

你好,可以这样编程]#includeintmain(){inti,sum=0;//定义循环变量和存放求和的变量sumfor(i=1;i

store0tosume,sumofori=100to1000ifi%2=0sume=sume+i&&偶数累加elsesumo=sumo+i&&奇数累加endifnext"100~1000偶数累加和=

dimnum3,num7asintegerfori=1to1000ifimod3=0thennum3=num3+1endififimod7=0thennum7=num7+1endifnext最后num

publicclassa{publicstaticvoidmain(Strings[]){intsum=0,count=0;for(inti=100;i0)continue;sum+=i;count+

#includevoidshunum(inta){inti;for(i=2;i

1su=0;fori=1:100ifmod(i,5)==0su=su+i;endendfprintf('所求和为：%d',su);2a=1;b=10;disp('x(1)=1\nx(2)=10');f

intmain(void){\x09intsum=0,i;\x09for(i=1;i

#includeusingnamespacestd;intmain(){intsum=0;for(inti=1;i

#include<stdio.h>intmain(){inta,b,c,i,number=0;for(i=100;i<1000;i++){a=i/100;b=i/10%10;c=i%

软件开发里也分方向啊,不知道你是想学哪方面的,是java呢还是.net的,里面的关键字其实也不是太多,都是些常用的,经常使用了就自然而然的记住了,不用刻意去记那些东西,我也学过软件编程,.net方向的

functiona=myconv(b,c)bs=size(b);cs=size(c);i=any(bs-cs);ifierror('error')endi=any(~(bs-1));ifierror(

#includeintmain(){\x09inti,sum=0;\x09for(i=1;i

#include <stdio.h>#include <iostream>#include <vector>#include

#includeusingnamespacestd;intsum(inta[],intx){inti,b=0;for(i=0;i>m>>n;for(i=0;i

#includeintmain(){inti,j=0;for(i=1;i

inti=0;for(j=1000;j

#include"stdio.h"#includevoidmain(){ints2;voidsushu(ints2);printf("请输入上限");scanf("%d",&s2);sushu(s2)

clears=0fori=2to1000step2s=s+inext或者clears=0fori=1to1000ifi%2==0s=s+iendifnext

sum=0;>>fori=1:100sum+=i;end>>sum

Dimi,sAsIntegerFori=2To100step2s=s+iNexti