编程实现:产生10个10--100之间的随机整数
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/21 08:35:42
简单的方法用指针指向每一个数组,然后用指针来调用数组中的数来操作.
int main(){\x09int a[10] = {0};\x09for (int i=1; i<10; i+
PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(
Subtest()DimiAsInteger'声明i是整数变量Fori=1To10'循环1到10Cells(i,1)=i'赋值NextEndSu
#includeintmain(){intt=1;inti;ints=0;for(i=2;i
packagetest;importjava.util.Random;publicclassrandomNum{publicstaticvoidmain(String[]args){chec
PrivateSubCommand1_Click()Dima(50),i,nRandomizeFori=1To50a(i)=Int(Rnd*191)+10Printa(i);IfiMod10=0The
'本人亲测可行Private Sub Form_CLICK() Dim arr(9) As In
代码如下:dimi,a(100)asintegerrandomizefori=0to99a(i)=int(rnd*(100-1+1))+1'这是一个公式,next
dimiasinteger,nasinteger,sasinteger,kasintegerfori=1to10k=val(inputbox("请输入一个整数:"))ifkmod2=1thenn=n+
Dimy%,x%Fori=1To10x=Int(Rnd*100)'[0,99]Printx;Ifi=1Theny=xElseIfy>xTheny=xEndIfNextiPrint"最小值";x如果是N
#includemain(){inti,n=0,sum=0;inta[10];printf("n\输入10个数:");for(i=0;i
intmain(){inttemp;/*用于临时保存输入的整数*/intsum=0;/*用于求和*/intcount=0;inti;/*输入这10个数*/for(i=0;i{scanf("%d",&t
窗体加一按钮,一个文本框PrivateSubCommand1_Click()RandomizeFori=1To100Text1.Text=Int(Rnd*90)+10NextEndSu
#include<stdio.h>int main (){ int i = 0,a[10]&
#include"stdio.h"main(){intinteger,i,max,min,sum;max=0;min=100;sum=0;for(i=1;i100||integermax)max=in
#include#includevoidmain(){inta[10];inti,j,temp;cout
Dimi,sAsIntegerFori=2To100step2s=s+iNexti
PrivateSubCommand1_Click()DimArr(9)AsLong'用于存放产生的10随机数DimiAsLongDimnMaxAsLong'用于存放最大的偶数DimnMinAsLong
usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespaceConsoleApplic