编程从键盘输入一个整数值k,再循环输入k个整数num,统计其中

voidmain(){inta[10];intmax=0;inti;for(i=1;ia[max])max=i;}if(max!=0){i=a[0];a[0]=a[max];a[max]=i;}/*最

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

#include"stdio.h"doublef(intk,intn){doublei=n;intj;for(j=1;j再问：i=f(k,n-1)+i;这句不对再答：程序写错了，应该是这样#inclu

#includemain(){intm,n,k,j,s,t;printf("pleaseinputthenumberofm,n,k\n");scanf("%d",&m);scanf("%d",&n);

主函数这样intmain(){intsum=0;inti;intn;printf("Pleaseinputanumber:");scanf("%d",&n);for(i=1;i

#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09a=a+b;\x09b=a-b;\x09a=a-b;\x09printf("%d%d"

1,#includelongfoo(intn){if(1==n)return1;returnn*f(n-1);}intmain(void){intm,n,k;scanf("%d%d%d",&m,&n,

#includevoidmain(){\x09inta;\x09scanf("%d",&a);\x09printf("%d*%d=%d\n",a,a,a*a);}//运行情况：33*3=9请按任意键继

inputaifmod(a/2)=0?a/2+3endif

#include#includevoidmain(){intn,s,j,i;printf("inputn(n

#include#includeintmain(){floata,b;printf("plesaseenteranumber\n");scanf("%f",&a);if(a>=1000){printf

inta,b,max;scanf("%d",&a);scanf("%d",&b);max=Max(a,b);intMax(inta,intb){returna>b?a:b;}再问：确定吗这个答案？再答

#includeintk;voidshow(){chara;printf("Pleaseinputtheletter.\n");scanf("\n%c",&a);printf("Theletter's

我觉得这才是楼主的意思吧,首先判断能否同时被5和6整除,如果不能再单独判断是否能被5或者6整除.importjava.util.Scanner;publicclassTest{publicstatic

staticvoidMain(string[]args){intx;intres;x=Int32.Parse(Console.ReadLine());if(x

importjava.applet.*;importjava.awt.*;importjava.awt.event.*;publicclassTest3_2extendsAppletimplement

main()　　{inta,b,c;　　printf(“请输入三个整数：”);　　scanf(“%d,%d,%d”,&a,&b,&c);　　if(aif(belseprintf(“max=%d\n”,

intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(