编写程序计算: 1-1 3 1 5的前n项之和,其中n由键盘输入.-搜答案-智慧作业帮

1.用dowhile循环写出计算100以内奇数和的程序clearsettalkoffs=0i=1dowhilei

PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问：x=x+a*0.2+3000*0.2怎么都乘0.2呀？

/*1-2/3+3/5-4/7+5/9-6/11+.的前n项之和*/intmain(intargc,char*argv[]){intnum_n=1;inti=0;doubleresult=0.0;pr

intmain()doubleresult;inti;intn;scanf("%d\n",n);for(i=1;i

doublef(doublex){doubles=.0;if(x

#includeusingnamespacestd;#include/*编写程序,计算并输出下面数列前20项的和,结果取3位小数.(C++)2/1,3/2,4/3,5/4,6/5,7/6,8/7,……

doublenum1,num2,num3,sum;num1=num2=num3=sum=0;for(intii==0;ii再问：看的不是太明白哦，能写的再清楚一点吗？再答：doublenum1,num

#includeusingnamespacestd;voidjishu(intn){intk=1;inta=1;doubles=0;for(inti=0;i

sum=sum+1/(5*i+1);这一句,1/(5*i+1)的值是整数的,所以它一直是0这样好像可以sum=sum+(double)1/(5*i+1);

程序框图如下：程序如下：s=1i=3DOs=s*ii=i+2LOOPUNTILi＞99PRINTsEND

#include"stdio.h"voidmain(){doublea,n,s=0;for(n=1;n

#include"stdafx.h"voidmain(){ints=0;for(intn=1;n

问题太多.1,第四行doubleresult,product,case;中case不能作变量名,保留字.2,第十行result=fact(i);函数参数太少,你下面定义的函数应该有2个参数3,case

“i=1”---->"i==1","i=2"------>"i==2"

编写程序,计算S

;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX

PrivateSubCommand1_Click()Dimsum,xx=0sum=0Fori=1To200x=x+2*(i-1)sum=sum+xNextPrintsum'结果为2666600EndS

longn=0;for(inti=1;i

1.dimi,jasIntegerfori=1to20j=j+i*(i+1)*(i+2)nextimsgboxj

#include <stdio.h>long u, v;void addrat(int, int);void lowterm()

#include"stdio.h"voidmain(){floatans=0;inti;for(i=1;i