编写程序求无理数e的值并输出float fun()

voidmain(){intx,inty;printf("请输入X的值:");scanf("%d",&x);printf("\n");if(x

#include<stdio.h>void main(){ int i,j,c[2][3]; int a[2][3]={{12,23,34

本人初学,答的不好的地方请见谅,程序代码如下：importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs

#include#includeintzxgb(inta,intb){inti;for(i=1;a*i%b;++i);returna*i;}intmain(){inta,b;printf("%d%d"

程序如下：#includevoidmain(){\x05inti;\x05doublesum=0.0;\x05for(i=1;i\x05{\x05\x05sum+=1.0/i;\x05}\x05pri

#include <stdio.h>//不知道 你加头了没void fun(int n){\x05float e = 

#includevoidmain(){inti,j=0;for(i=1;i

#includemain(){inti=1;floattemp=1;floatsum=0;while(temp>=1e-6){sum+=temp;temp/=i;i++;}printf("e=1+1/

解题思路：赋值语句解题过程：varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph

#include<stdio.h>#include<MATH.H>boolprime(intx);voidmain(){intm,n,count=0,sum=0;scanf("

你这个问题也太简单了吧,看来你是初学者：#includevoidmain(){inta,b,t;scanf("%d%d",&a,&b);t=a;a=b;b=t;printf("\n%d%d\n",a,

test{publicstaticvoidmain(Stringargs[]){longsum=0,a=1;longi=1;while(i=1)sum=sum+a;i++;a=a*i;}System.

若梯形的上底为a、下底为b、高为h，面积为S，故程序语句如下：INPUT“梯形的上底，下底，高”；a，b，hS=（a+b）*h/2PRINT“正方形的面积为：”；SEND

publicclassFactorial{privateintresult=1;publicintfactorial(intnumber){if(number==1)returnresult;else

解法1:#includeintF1(){return50*(1+99)/2;}intF2(){return50*(2+100)/2;}voidmain(){printf("Oddnumbersum=%

elsey=3*x+1；后面的封号是汉字的

#includemain(){inti=1;floattemp=1;floatsum=0;while(temp>=1e-6){sum+=temp;temp/=i;i++;}printf("%f",su

#includevoidmain(){floata,x,z;scanf("%f,%f",&a,&x);printf("pleaseinputa,x:,.\n");z=1.0/2*(a*x+(a+x)/

#include"stdio.h"intmain(){intcountou,countji=0;inti=0;for(i=1;i

dimaasdouble,basdouble,casdoubledimx1asdouble,x2asdoublea=val(inputbox(""))b=val(inputbox(""))c=val(