编写程序求2! 4! 6! -- 2n!的和

#includevoidmain(){floatsum=0.0;intn=0,sign=-1;scanf("%d",&n);for(floati=1;i

楼上的两个答案都不对.都忘了将n-1.publicclassTestNFactorial{publicstaticvoidmain(String[]args){inttarget=9876;run(t

PrivateSubCommand1_Click()DimnAsLong,xAsSingle,yAsSingle,y2AsSingle,sumAsSinglex=Val(InputBox("请输入一个

#include#includeintmain(){inti=2;intn=0;ints=0;for(;s+i再问：你好。问下system("pause");这句什么意思？再答：暂停控制台。在

#includevoidmain(){inti,a=0,sum=0;for(i=1;;i++){a+=1;sum+=a;if(sum>1000){printf("n:%d\nsum:%d\n",i,s

vars,i,n:long;beginwrite('N=');readln(n);s:=0;fori:=1tondos:=s+i;writeln(s);end.

#include"stdio.h"#include"math.h"doublefact(intn)//求n的阶乘,用double的目的是为了提高表示数的范围{ doublesum=1.0;&

vc写的#includevoidmain(){inti;doubles=0;for(i=1;i

classMAXn{publicstaticvoidmain(Stringargs[]){intk=1,sum=0;while((sum+=k)

varpp=0,kk=0functionf1(x){pp=x*xreturn(pp)}functionf2(y){kk+=yreturn(kk)}for(vari=1;i

PrivateSubCommand1_Click()Dimn%,sum!,fact!sum=0n=InputBox("输入n:","提示信息",1)IfnMsgBox"数据有误!",48,"警告!"E

#includeintmain(){intsum=1,i=1;while(i

我用php语言写的.分两个步骤,一个是计算每个节点的值,用递归算法.一个是节点的累加,用循环算法.这么好的答案,不给分,没良心.再问：谢谢了，我没说清楚，我现在学的是c++语言，真的很感谢

用什么语言写?下面的C版本：doublefact(intn){doublea,s;inti,j;for(i=1;i>n;i++){a=1;for(j=1;j>i;j++)a=a*j;s=s+a;}re

ints=1;intn=1;while(s

#includeintmain(){inti,j,n,k=0;scanf("%d",&n);for(i=2;i

Console.Write("请输入n=");intn=Convert.ToInt32(Console.ReadLine());intsum=0;for(inti=1;i{sum*=i;}Consol

#includeintfun(intn){returnn==0?1:n*fun(n-1);}intmain(void){inti,sum=0;for(i=1;i

intfun(intn){doublesum=0.0;intk=1;for(inti=1;i

settalkoffclearinput"输入N值："tons=0FORi=1TOna=1FORj=1TOia=a*jENDFORs=s+aENDFOR"1!+2!+3!+...+n!=",ssett