编写求组合数的函数fun(),并调用该函数求解5个数每次取3个数的组合

intfun(intn){inta=n,b=0;while(a>0){b=b*10;b=b+a%10;a=a/10;}printf("%d",b);getch();return0;}或者把后三行删掉,

floatfun(intn){\x09inta[30];\x09floatsum=2/1;\x09a[0]=2;\x09a[1]=3;\x09for(inti=2;i再问：floati;doublea

intfun(intn){intm=1,sum=0,i,j;for(i=1;i

#include"stdafx.h"#includeintsct(intm,intn){inttemp,a,b;if(m>y;g=sct(x,y);cout再问：是fun函数吗？测试用的主函数

#includeintfac(intx){intret=1,i;for(i=1;i

PrivateSubfun()ifimod2=0thenforx=itoastep2s=s*xnextxelseforx=(i+1)toastep2thens=s*xnextxendif试试看行不行吧

voidfun(longn){intwan,qian,bai,shi,ge;//定义各数位longnixushu;//定义逆序数wan=n/10000;qian=(n-wan*10000)/1000;

intfun(intn){inta=n,b=0;while(a>=1){b=10*b+a%10;a=a/10;}returnb;}已经调试通过了哦!

调试过了,如果需要小数,把int换成float就行了#include"stdio.h"intSub(inta,intb){intc=a-b;returnc;}intmain(){inta,b;prin

PrivateFunctionSumA(ByValaAsInteger)AsLongDimiAsInteger,NAsIntegerFori=500To600IfiModa=0ThenN=N+iNex

上面的错了应该是intfun(){inti,sum=1;for(i=1;i

#include#includevoidswap(intc[],intlen){inti=0;inttmp;for(;i{tmp=c[i];c[i]=c[len];c[len]=tmp;}}intmu

#include <stdio.h>#include <stdlib.h>#include <math.h>double f

#include<stdio.h>unsignedlongcombinNum(intm,intn){ inti; unsignedlongx=1; if(n&

请楼主参考采纳intfun(intt){inti;intcurrent=0;for(i=1;totalt)break;current+=i;}returncurrent;}

问题太多.1,第四行doubleresult,product,case;中case不能作变量名,保留字.2,第十行result=fact(i);函数参数太少,你下面定义的函数应该有2个参数3,case

Functions(ByValaAsInteger,ByValbAsInteger)AsIntegerDimiAsIntegerFori=1To1000IfiModa=0AndiModb=0Thens

1.intf1=0,f2=1,f3;2.returnf3;继续写：f3=f1+f2;f2=f3;f1=f2;

functionfun(d,h){if(d

intfun(w){intsum=0;for(inti=1;i