编写函数实现从整数m到n能被3整除但不能被5整除的数输出
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publiclongpower(intm,intn){if(nreturnm;elsereturnpower(m,n--)*m;}
#includeintdigit(intn,intk){returnk>1digit(n/10,k-1):n%10;}intmain(){printf("%d",digit(12345,3));}
longpower(intm,intn){doublep=1;if(n>0){p=m*power(m,(n-1));returnp;}}voidmain(){intm,n;longk;scanf("%
intT(intn,intm){\x05if(m>10||m\x05intx=n;\x05intk;\x05intresult=0;\x05intpowNum=1;\x05do{\x05k=x%10;
functiony=myfunction(m,n)%m
fun(){for(inti=1;i
完整程序如下:#include#defineN100intmain(){intn,m,i,num[N],final[N];intmove(intn,intm,intfinal[],intnum[]);
#include<stdio.h> int getMaxNumber(int n) { int k;
#include<iostream.h>void main(){ int n; &nbs
自己敲的,你看看是不是你要的……我吃饭去了,有事发邮件479292539@qq.com#include#defineM4#defineN5voidmain(){inta[M][N],i,j;intnu
#include#includevoidmain(){intn,s,j,i;printf("inputn(n
#includeinta[50];intfun(intm){intn=0;for(inti=1;i
源码如下:#includeintsum(inta,intb){\x09returna+b;\x09}intmain(){\x09intm=1,n=2,k=3;\x09intt=sum(sum(m,n)
Functionsum(n)AsDoublesum=0Fori=1TonIfiMod2=0Thensum=sum+i*iNextEndFunction
//新建一个m文件:function[y1,y2]=fun2010(m,n)y1=gcd(m,n)y2=lcm(m,n)end在命令窗口中输入:fun2010(3,6)回车y1=3y2=6
#includeintfun(intM,inta[]){intn=0;inti;for(i=1;i{if(i%7==0||i%11==0){a[n]=i;n++;}}returnn;}intmain(
我只会MATLAB,假设数组记为x,数组中元素各不相同[a,b]=max(x);%a是最大值,b是最大值的下标,即序号x(b)=[];%删除x的最大值次大值=max(x);%次小值类似[a,b]=mi
#include#includeusingnamespacestd;intcmn(intn,intm){\x09if(m==1)\x09\x09return1;\x09elseif(n==1)\x09
function[ym]=myfile(n)m=0;fori=1:nifmod(i,4)==0&&mod(i,5)>0&&mod(i,3)>0m=m+1;y(m)=i;endend
n阶乘的函数factorial(n)再问:要过程,谢谢再答:NN=1whilen>0NN=NN*n;n=n-1;endNN