编写函数,找出5*5矩阵对角线元素的最大值

#include"stdio.h"#defineM5//矩阵阶数voidmain(){inta[M][M],i,j,sum=0;printf("请输入%d*%d矩阵：\n",M,M);for(i=0;

intnSum=0;for(inti=0;i

#include<stdio.h>#define N 3 //数组宽长void fun(int a[N][N]){  

#include"stdio.h"voidmain(){intmagic[5][5]={{17,24,1,8,15},{23,5,7,14,16},{4,6,13,20,22},{10,12,19,

functionmm(A,B)s=size(A);h=s(1);w=s(2);C=zeros(h,h);fori=1:hforj=1:hform=1:wC(i,j)=C(i,j)+A(i,m)*B(m

fun(){inta[3][3],i,j,n=1;printf("pleaseinputa[3][3]:\n");for(i=0;i

intMax_Min(int*array,intarrayNum){intmax;intmin;if(arrayNum==0){return-1;}else{max=array[0];min=arra

#include"stdio.h"intmain(){intshuzu[4][4];inti;intj;intmaxs;intsum=0;for(i=0;i

doublefun(){doublea[4][4];doublesum=0;inti,j;for(i=0;i

#includeintmain(){inta[4][4]={{7,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,5}};inti,sum=0;for(i=0;i{sum+=a[i

PrivateSubForm_Click()Dima()AsIntegerDimi,j,max,n,mRandomize(time)n=InputBox("n=")m=InputBox("m=")Re

#include#defineN3voidfun(int(*p)[N]){inti;for(i=0;i

,j,minv,mini,minj,sum=0;inta[4][4];printf("请输入矩阵中的16个数：");for(i=0;i<4;i++)for(j=0;j<4;j++)scan

#include <iostream>#include <iomanip>#include <ctime>using nam

http://zhidao.baidu.com/question/394338851.html?oldq=1

main(){inta[3][3]={{1,2,3},{4,5,6},{7,8,9}}inti,j;intsum=0,s=0;for(i=0;i

voidmain(){inti,j,minv,mini,minj,sum=0;inta[4][4];printf("请输入矩阵中的16个数：");for(i=0;i<4;i++)for(j=0;

c中数组在定义时就应分配确定的大小,加一句#definem5//矩阵大小为5#includeintfun(intm,inta){inti,sum=0;for(i=0;i再问：C-free编译不通过饿。

//zd_40.cpp:Definestheentrypointfortheconsoleapplication.//#includeintmain(intargc,char*argv[]){inti

#include"math.h"#include"stdio.h"intm=1,i,j,a[5][5];voidmain(){for(i=0;i