作业帮编写一个递归函数,计算如下定义的函数f
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/16 02:58:11
#include"iostream.h"voidmain(){doubleF,c;coutF;c=(F-32)*5/9;cout
#include"stdio.h"intfact1(intn){if(n==1||n==0)return1;elsereturnn*fact1(n-1);}intfact2(intn){inti,t=
// C++int F(int n) {if (n == 0) return 1;else if
longadd(intn){intt=n-1;if(t>1){longresult=n*t;longsum=result+add(t);returnsum;}else{returnn;}}楼上的方法,
#includedoubleH(intn,doublex){if(x>1){if(n==0)return1.0;//H0(x)=1;if(n==1)return2.0*x;//H1(x)=2x;//直
cludestdio.hvoidmain(){intmax_4(inta,intb,intc,intd);inta,b,c,d,max;printf("Pleaseenterintergernumbe
#includeusingnamespacestd;doublefun(intn,doubleh){if(n==1)returnh;elseif(n再问：usingnamespacestd;这句
functionyout=myfun1(x,D)%myfun1helph=5%|-h,x>D%y=f(x)=|h/(D.*x),|x|
#includeintFibonacci(intn){if(n==1||n==2)//递归结束的条件,求前两项return1;elsereturnFibonacci(n-1)+Fibonacci(n-
#includelongfac(intn){inti;longx=1;for(i=2;i再问：谢谢咯！可是我说的是递归法哦！再答：#includelongfac(intn){if(n==0)retur
#include <stdio.h>char* dg(char* instr, char* outstr, char*
C描述functionttt(n){ returnn>1?n*ttt(n-1):1;}使用方法:ttt(21);
#includeintfact(int);main(){inti,sum=0;for(i=1;i
intSumNums(intnum){if(num
#includeintsum_of_square(intn){\x09intsum=0;\x09if(n
非递归的递推函数：longfun1(intn,intx){longa,b,t;inti;if(n==0)return1;if(n==1)return2*x;a=1;b=2*x;for(i=2;i1)r
1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n
#includemain(){intn,i,j,k;while(scanf("%d",&n)==1){if(n==1||n==2){printf("%d\n",1);cont
#include <iostream>using namespace std;long fact(int n){ &