编写一个计算矩形面积的函数,在主函数中输入长和宽,调用该函数输出该矩形的面积.

#includedoublecalRectArea(doubledWidth,doubledHeigh){returndWidth*dHeigh;}voidmain(){doublea,b,mul;s

PrivateFunctionSUM(Fir_LAsDouble,Fir_SAsDouble,Scend_LAsDouble,Scend_SAsDouble)AsDoubleSUM=Fir_L*Fir

intarea(intx,inty){returnx*y;}intgri(intx,inty){return2*(x+y);}

#include<stdio.h>double zc(double x, double y){    ret

#includeusingnamespacestd;floatmianji(floata,floatb){returna*b;}floatzhouchang(floata,floatb){return

publicclassTest{publicstaticvoidmain(String[]args){System.out.println("圆的面积："+area(2));System.out.pr

#include <stdio.h>float area(float r){  return 3.14159 *&nb

这个还是比较简单的,学过C＋＋的人基本都会的,本来可以帮你设计一个,只可惜电脑上没有装软件啊,哎.又是一个自己懒得动手的孩子.

#includeintgetArea(intlen){\x09returnlen*len;}intmain(){\x09intn;\x09intarea;\x09\x09printf("请输入边长:\

public class Test {\x09public static double area(double length,do

classTriangle{private:\x05doublea;\x05doubleb;\x05doublec;public:\x05Triangle():a(0),b(0),c(0){}\x05

#include#include#includeusingnamespacestd;classbase{public:virtualvoiddisp()=0;};classtriangle:publi

function [ s ] = solve_area( a,b,c )  p=(a+b+c)./2;&nbs

publicclassRectangle{\x09\x09privateintw;\x09\x09privateinth;\x09\x09publicRectangle(){\x09\x09}\x09

chara;scanf("%c",&a);switch(a){case'y':圆形case'c':长方形cash'z':正方形}

voids(folata,folatb,folatc){folatp;p=(a+b+c)/2;S=√[p(p-a)(p-b)(p-c)];returns;}

//计算矩形的面积publicclassRectArea{\x09publicstaticdoublegetArea(doublewidth,doublehigth){\x09\x09doublear

#include#include#definePI3.14159usingnamespacestd;classShape{public:virtualdoublegetArea()=0;protect

//使用海伦公式#include/*ForIO*/#include/*Forsqrt()*/intmain(void){doublea,b,c,p,s;printf("请输入a,b和c：");scan

#includemain(){doublea,b,z,c;cin>>a>>b;//输入长和宽z=a*b;//计算面积c=2*(a+b);//计算周长cout