编写一个程序,找出被2,3,5整除的数

input"请输入第一个数："toainput"请输入第二个数："tobinput"请输入第三个数："toc?"最大值为：",max(a,b,c)

#includevoidmain(){inti=2,result=1;for(;i

30n+1316191121151181211241271301

privatesubform_click()dimnaslong,snaslongn=inputbox("请输入n")fori=0tonsn=sn+2*i+1nextmsgbox"1+3+5+...(

#includevoidmain(){intn;printf("input:\n");scanf("%d",&n);if(n%3==0&&n%5==0)printf("yes\n");elseprin

//这样就ok了,刚写的code,测试通过,如果有疑问,欢迎交流#include<iostream>using namespace std;int main(

PrivateSubCommand1_Click()Dimi%Fori=100To999IfiMod7=0AndMid(CStr(i),2,1)="2"ThenPrintiNextEndSub再问：M

SubMain()MsgBoxFunc(100,2,5)'按照要求写的例子EndSubRem参数(最大值,被整除的数的数组)FunctionFunc(n&,ParamArrayx())Dimi&,b&

#include#includeintf(intn)//n为素数则返回1,否则返回i-1{inti=2;while(i

VB程序PrivateSubCommand1_Click()Dima,iAsIntegeri=1Whilei<50s=s+(i+1)/ii=i+1WendPrint"s=";sEndSu

varn,i,min,max,maxi,mini,s:integer;x:array[1..100]ofinteger;ans:real;beginreadln(n);fori:=1tondoread

#includeintmain(){intsum=1,i=1;while(i

程序框图如下：程序如下：s=1i=3DOs=s*ii=i+2LOOPUNTILi＞99PRINTsEND

pt = {2, 2};ContourPlot[ Sqrt[(x - pt[[1]])^2 + (y -&nb

voidmain(){intn;printf("请输入一个整数:");scanf("%d",&n);if(n%3==0&&n%5==0&&n%7==0)printf("\n此数能被3,5,7整除\n"

编译环境为：devcpp5.0++#include#include#includeintsearch(intnumber){intge,shi,bai,i,count=0,a;doublenum_sq

publicclassTestArray{publicstaticvoidmain(String[]args){intm=0;for(inti=1;iintn=1;for(intj=1;jn=n*j;

/>vart;varl=prompt('请输入边长',3.5);t=3.1415926*(l/2.0)*(l/2.0);document.write("边长:"+l);document.write("

main(){intn;scanf("%d",&n);if(n%3==0&&n%5==0)printf("能整除\n");}追问：输不了汉字啊?回答：有的环境是不能输入汉字的

#includeintmain(){intsum=0;inti=1;intj=1;for(;i