编写一个程序,以友元函数方式计算一个点到一条直线的距离-搜答案-智慧作业帮

CLEARSETTALKOFFINPUT"请输入半径:"TORL=2*PI()*RS=PI()*R*R"半径为R的圆的周长为:",L"半径为R的圆的面积为:",SSETTALKON

#include <iostream>#include <stdlib.h>int main(){int start =&nb

1.思路：用一个字符串数组储存输入的数据，并分别输出。程序：Vara:array[1..3]ofstring;i:integer;BeginFori:=1to3doReadln(a[i]);Fori:

#includeclassangle{private:floatx,y,z;public:angle();voidthreeb(floata,floatb,floatc);friendvoidcoma

(x,y)=x+y(x>=0&y>=0)f(x,y)=x+y*y(x>=0&y

#include <stdio.h>#include <string.h>#include <stdlib.h>void c

#includemain(){doublex,y;scanf("%lf",&x);if(x

#include#includeintis_prime(intn);intmain(){inti,sum=0;for(i=2;i

programa4;vara,b,c:integer;beginreadln(a,b,c);if(((a>0)and(b>0)and(c>0))and((a+b>c)and(a+c>b)and(b+c

input(x)ifx

这个可以这样做~cleara=rand(10,1);%产生一组随机数b=rand(10,1);%产生另一组随机数b=b-(dot(a,b)/dot(a,a)).*a;%可以使用施密特正交化的方法转化d

varn,i,min,max,maxi,mini,s:integer;x:array[1..100]ofinteger;ans:real;beginreadln(n);fori:=1tondoread

#includeusingnamespacestd;//传值调用voidchuanzhi(inta,intb){intt=a;a=b;b=t;cout

#include#includevoidTemperatures(doublefahrebheit){doublecelsius,kelvin;celsius=1.8*fahrebheit+32.0;

pt = {2, 2};ContourPlot[ Sqrt[(x - pt[[1]])^2 + (y -&nb

//第1题#include#includeusingnamespacestd;intmain(){inta;cin>>a;cout

/>vart;varl=prompt('请输入边长',3.5);t=3.1415926*(l/2.0)*(l/2.0);document.write("边长:"+l);document.write("

#include <iostream>#include <iomanip>#include <ctime>using nam

这就是求分段函数的值.x

assumecs:code,ds:datadatasegmentresultdb0,1,4,9,16,25,36,49,64,81xdb4dataendscodesegmentstart:movax,