java设计一个矩形类,有长和宽两个属性,能够计算每一个矩形的面积和周长:,

publicclassRectangle{privatedoublewidth;privatedoublelength;publicdoublegetWidth(){returnwidth;}publ

staticvoidjuxing(doublex,doubley){//x和y是长,宽doubled=2*x+2*y;//周长doubles=x*y;//面积System.out.println("矩

packagecircle;publicclassEasy{privatedoubleBj;privatestaticdoublePi=3.1415;publicdoublegetBj(){retur

1作一条线段AB等于四厘米2过A作一条射线AE垂直于AB3在AE上截AD等于二倍根号五减二厘米4过D作AB的平行线DC过B作AD的平行线BC5ABCD就是所求矩形

这个还是比较简单的,学过C＋＋的人基本都会的,本来可以帮你设计一个,只可惜电脑上没有装软件啊,哎.又是一个自己懒得动手的孩子.

import java.awt.*;import java.awt.event.ActionEvent;import java.awt.event.ActionListe

1,20πx+πx²=60x+3x²2120x+80x-4X²+60x+3x²=-X²+260X=516解得X=2或者x=258(舍去)详细做法嘛.还

1.S=[π(R²-r²)]/2×2=π[(10+x)²-10²]=20πx+πx²=3x²+60x2.2400/5+36=60x+3x&#

这个是三角圆和矩形的,你参考下,可以计算面积和周长publicclassHHsa{publicstaticvoidmain(String[]args){Geometricg=newTriangle(3

public class Test {\x09public static double area(double length,do

classCircle{protecteddoubleradius;publicCircle(){radius=0;}publicCircle(doubleradius){thi

要求是正方形,对角线长度就是直径长=宽=3*根号2*根号2=6,此时面积=6*6=36

#includeclassPoint{private:doublex,y;public:Point(doublexx,doubleyy){x=xx;y=yy;}doublegetX(){returnx

给你两种写法第一种：#include#includeclassRectangle{public:Rectangle(intleft,intbottom,intright,inttop);Rectang

#includeusingnamespacestd;classRectangle{private:intheight;intwidth;public:intgetC(){return(he

publicclassRectangle{\x09\x09privateintw;\x09\x09privateinth;\x09\x09publicRectangle(){\x09\x09}\x09

publicclassrectangle{doublea;doubleb;doubleperimeter;doublearea;publicrectangle(doublea,doubleb)//长方

//计算矩形的面积publicclassRectArea{\x09publicstaticdoublegetArea(doublewidth,doublehigth){\x09\x09doublear

用绳子分别量一下上下边和左右边,如果分别相等,说明这个窗子至少是平行四边形.再量一下两个对角线,如果还相等,则说明是矩形.因为只有矩形满足对角线相等,且对边相等的条件.

publicclassNumberCompute{publicdoublecalculate(intn){doubleresult=0;for(inti=1;i