java怎么从键盘输入整形正数

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

#include#includeintmain(){\x09doublex;\x09scanf("%lf",&x);\x09printf("%lf\n",sqrt(x));\x09return0;}

"float*Grade(float*num,inti)//用来冒泡排序num传入数组指针,i传入数组个数{intj,k;floattemp;for(j=0;j<i;j++)for(k=0;k&

#includevoidmain(){\x05doublenumber[20]={0};\x05inti=0,a=0,b=0;\x05doublesum=0,average=0;\x05cout

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

import java.util.Scanner;  public class TestJT {  public&nbs

本人初学,答的不好的地方请见谅,程序代码如下：importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

#includevoidmain(){inta[10],i,*m,*n,k=0;\x09printf("请输入十个数\n");for(i=0;i

判断从键盘输入的三个数能否构成三角形.如果是特殊的三角形（如等边、等腰、直角,等腰直角）需要能判断出来.

intsum_p=0,sum_n=0;for(inti=0;i{inta;cin>>a;if(aelseif(a>0)sum_p++;}cout

调出来了：int[]b=newint[n];这个语句应该是上面的这个,要申请n个空间,不是n-1,否则会数组下标越界.运行后,先输入一个整数n,表示下面还要输入整数的个数,然后在输入n个整数,求这n个

importjava.util.Scanner;publicclassTest01{publicstaticvoidmain(String[]args){Scannerscan=newScanner(

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

#includevoidmain(){inta[100],max,min,n,i;scanf("%d",&n);for(i=0;i

提示；1.用数组接收输入的数2.IF（负数）用计数变量统计负数个数ELSE平均数

importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs[]){doublep,s,l,r;Strin

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S

//从键盘输入10个实数,求正数之和和负数之和//#include#defineN10voidmain(){\x09floata[N],sum_add=0,sum_minus=0;\x09inti;\