JAVA实现随便输入一个四位数判断是平年还是闰年,第一位不能为零怎么简便一点
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#includeusingnamespacestd;voidmain(){inta[4];cout再问:还是有好几个错误再答:#includeusingnamespacestd;voidmain(
inti=2123;intone,two,three,four;one=i%10;//各位two=(i/10)%10;//十位three=(i/100)%10;//百位four=(i/1000)%10
PrivateSubCommand1_Click()a=cint(inputbox("输入一个四位数"))ifa9999thenmsgboxa&"不是四位数!":exitsubfori=1to4b=b
#includevoidmain(){inti,j,k,m,n;printf("inputanumber:\n");scanf("%d",&n);i=n/1000;j=(n%1000)/100;k=(
创建两个text控件和一个command按钮控件再输入以下代码PrivateSubCommand1_Click()Fori=1ToLen(Text1.Text)a=Mid(Text1.Text,i,1
publicstaticvoidmain(String[]arg){intk=0;intm=0;System.out.println("输入一个四位数");Scannerinput=newScanne
#include#includeintmain(void){intn,sum=0,count=0,s;printf("输入一个整数:");scanf("%d",&n);while(n){s
#includeintmain(){inta[4];inti;printf("Pleaseinpuetthe4numbers:\n");for(i=0;i{printf("PleaseInpuetth
#includeintmain(){intn,m;scanf("%d",&n);m=0;while(n>0){m=m*10+n%10;n/=10;}printf("%d\n",m);return0;}
importjava.util.Scanner;publicclassEncpryt{publicEncpryt(){Scannerscan=newScanner(System.in);System.
#include<stdio.h>int main(){int n,s=0;scanf("%d",&n);while(n){s=
3458threefourfiveeight
publicclassTestNum{publicstaticvoidmain(String[]args){Scannersca=newScanner(System.in);intnum=0;ints
intnum=4568;intshiwei=0,baiwei=0,qianwei=0,gewei=0;qianwei=num/1000;baiwei=(num%1000)/100;shiwei=(nu
数字操作:varn,s:integer;beginreadln(n);s:=0;whilen>0dobegins:=s+nmod10;n:=ndiv10;end;writeln(s);end.字符串操
#include#includeusingnamespacestd;voidmain(){chars[4];intn,k;cin>>s;sort(s,s+4);n=(s[0]-'0')*10
importjava.util.Scanner;classtest7{publicstaticvoidmain(Stringargs[]){Scannerscan=newScanner(System.
楼上说没错,while(X)是先进行X判断然后再执行{语句体},而do..while则是先执行do{语句体},再判断while(X),这样会导致do..while比while执行语句体的次数多一次再问
importjava.util.*;publicclassMath{publicstaticvoidmain(Stringargs[]){inta,b;Scannersc=newScanner(Sys
作为字符串形式读入比用整形读入好处理,而且数的位数不受限制(整型有数值超界问题)#includevoidmain(){chars[80];//最长80位数字inti,L;printf("pleasei