java作业输入三个整数,由小到大的顺序输出

publicclassFactorial{publicstaticvoidmain(String[]args){if(args.length!=1){System.out.println("请输入n值

先写个函数判断n1、n2、n3大小,假设n1再问：怎么弄出n1n2n3的大小啊再答：//传入三个参数n1、n2、n3的引用，程序运行完后满足n1

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

a+b>cabs(a-b)再问：能编个完整的给我吗？谢谢。新手，看不懂啊……不胜感激再答：#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0

//看好记事本写的Judge.javapublicclassJudge{publicstaticvoidmain(String[]args){try{if(args.length!=3){Sy

publicstaticvoidtest(){Scannersc=newScanner(System.in);longnum=0,negative=0,positive=0,sum=0;Listnum

import java.util.*;public class Demo{    public static 

.你把做为结束符的0也算进去了吧.在循环里判定一下,如果是0不做MIN==NUMif（NUM!=0）MIN=MIN

#includemain(){intm,n,p,t;printf("输入m,n,p的数值");scanf("d,%d,%d,&m,&n,&p");/*不知道你说的调整使得mp){t=m;m=p;n=t

importjava.io.*;/***输入整数n,输出由n行n列星号字符组成的三角形图案**@authoruser**/publicclassXing2{publicstaticvoidmain(S

publicvoidscanner(){\x09\x09intarr[]=newint[5];//存储输入数据\x09\x09inttemp;\x09\x09\x09\x09//用于数据交换\x09S

#includeusingnamespacestd;intmain(){\x09inta=0,b=0,c=0;\x09coutb>>c;\x09if(a>b&b>c)\x09{\x09\x09cout

#includevoidmain(){inta,b,c,min,max,cha;scanf("%d%d%d",&a,&b,&c);min=a;max=a;if(b>max){max=b;}if(bma

第一种方法用if判断的importjava.util.Scanner;publicclassA{\x09publicstaticvoidmain(String[]args){\x09\x09Syste

楼上说没错,while(X)是先进行X判断然后再执行{语句体},而do..while则是先执行do{语句体},再判断while(X),这样会导致do..while比while执行语句体的次数多一次再问

你叫唤的是指针指向,但目标abc的值没有改变#includemain(){inta,b,c,n;int*p1,*p2,*p3;scanf("%d%d%d",&a,&b,&c);p1=&a;p2=&b;

intnum1,num2,num3;floataverage;printf("pleasenum1,num2,num3:\n");scanf("%d,%d,%d",&num1,&num2,&num3)

import java.util.Scanner;public class Code{public static void main(Str

#include#defineN3voidmain(){inta[N],x;printf("Pleaseinputthreenumbers:\n");for(inti=0;i

#includevoidmain(){inta,b,c;printf("请输入三个整数,以空格分隔：");scanf("%d%d%d",&a,&b,&c);inttemp;if(a>b){temp=a