Java作业:从键盘输入一个数,判断是否是偶数,如果是偶数则输出
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importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)
packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu
importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System
publicstaticvoidprintNum(intn){for(inti=2;ij){if(i%j==0){m++;}}else{break;}}if(m<1){System.out.print
importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin
packagea1;importjava.util.Scanner;publicclassTest1{publicstaticfloatzhouchang(floatx,floaty){return2
importjava.util.Scanner;publicclassCircle{ publicstaticvoidmain(String[]args)
Scannerscanner=newScanner(system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy
importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整
从键盘输入一个自然数N(
#includeusingnamespacestd;intmain(){char*str=newchar[255];cin>>str;cout再问:看不等,我刚学编程再答:把输入的数字放到一个指针数组
判断从键盘输入的三个数能否构成三角形.如果是特殊的三角形(如等边、等腰、直角,等腰直角)需要能判断出来.
oolcalc(unsignedintn){if(n
packageABC;importjava.io.*;publicclassdistantmoon{publicstaticvoidmain(String[]s)throwsException{
BufferedReaderbuf=newBufferedReader(newInputStreamReader(System.in));System.out.print("请输入时间(注意格式必须为
publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this
其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望
#includeintfindmax(inta,intb){if(a>b)returna;elsereturnb;}intmain(){inta,b,c;scanf("%d%d%d",
classOddSum//定义类{publicstaticvoidmain(Stringargs[])//main方法{intsum=0;//定义一个整形变量for(inti=1;i
哥们怎么又是你来?再问:您会不会的啊再答:packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S