JAVA中编写方法求斐波那契数列第n项的值,并调用该方法求出第15项的值

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

Stringsentence="Iamtom";String[]words=sentence.split("");intcount=0;for(inti=0;i0){count++;}}System.

viewplaincopytoclipboardprint?publicclassFibonacci{/***@paramargs*/publicstaticvoidmain(String[]args

先定义一个2行9列的二维数组,可以看成是两个一维数,每个一维数组有九个元素,然后分别给两个数组赋值（1,2,3,4,5,6,7,8,9这些值）；最后就是两个数组间的元素分别相乘了,按一定顺序相乘即得乘

#includelongintfn(int);voidmain(){printf("%d",fn(10));}longintfn(intm){longinttemp;if((1==m)|(2==m))

importjava.util.Scanner;classRound{\x09publicdoubleperimeter(doubleradius){\x09\x09returnradius*2;\x

publicclassFibonacci{publicstaticvoidmain(Stringargs[]){inti=1,j=1;for(intn=1;n

if(number%3==0&&number%5==0){System.out.println("number"+能被三和五整除);}else{System.out.println("number"+

代码如下,我已经测试过了,给你加了注释.publicclassTest{publicstaticvoidmain(Stringargs[]){for(inti=100;i再问：------------

publicclassFibonacci{\x09publicstaticvoidmain(Stringargs[]){intn,fn;//n为第n项,fn为第n项的值java.util.Scanne

packageb;publicclassc80{publicstaticvoidmain(String[]args){inta,b,c,d,e,f;for(a=1;a

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

publicstaticdoublemultiple(doublea,doubleb){returna*b;}publicstaticdoubledvd(doublea,doubleb){return

第n个元素等于第n-1加n-2个元素调用递归实现啊

intnum=(int)(Math.random()*100);这是生存的随机数,边界值用判断去掉你要有数组存放1-100数值对应的英文然后根据得到的随机数在数据中去英文然后输出.

publicclassT{\x05/**\x05*@paramargs\x05*/\x05publicstaticvoidmain(String[]args){\x05\x05int[]arr={\x

package zhidao;import java.util.Arrays;import java.util.LinkedList;public class&

cleardimea[20]a[1]=1a[2]=1fori=3to20a[i]=a[i-1]+a[i-2]endforfori=1to30?a[i]if(i%5=0)?endifendfo

public class getWord{ public static void main(String[] args){&nbs

class Exel {    public static void main(String[] a