由键盘输入三个数,计算以这个数为边长的三角形面积
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#includeusingnamespacestd;voidmain(){inta,b,c;intt;couta>>b>>c;if(a>b){t=a;a=b;b=t;}if(a>c){t=a;a=c;
#include"stdio.h"main(){intA,B,C,min;printf("inputA,B,C:");scanf("%d%d%d",&A,&B,&C);min=A;if(min>B){
#include<math.h>main(){ floata,b,c,s,s1;printf("pleaseenter3reals:\n");scanf(&q
只要先选出最大的数,然后其他两个数相加大于这个数就可以构成三角形.然后w=(x+y+z)/2;area=sqrt(w*(w-x)*(w-y)*(w-z));
#includeusingnamespacestd;intmax(inta,intb){returna>b?a:b;}intmain(){inta,b;couta>>b;cout
#include"stdio.h"main(){inta,b;printf("请输入两个整数(a,b):");scanf("%d,%d",&a,&b);printf("和:%d\n",a+b);pri
#includemain(){inta,b,c,max;printf("input3numbers:");scanf("%d%d%d",&a,&b,&c);if(a>b)max=a;elsemax=b
#includeintmain(void){inta,b,c,t;printf("请输入三个任意整数:\n");scanf("%d%d%d",&a,&b,&c);if(a
你把你的代码带大括号试下.main(){inta,b,c;if(a
#include#include#defineN5intmain(){inti,j,a[10],sum=0,temp;floataverage;for(i=0;i
10-√330,10,10+√330
#includeintmain(void){intmax=0;while(1){intnum=0;scanf("%d",&num);if(num==0)break;max=num>maxnum:max
#include#include#defineMAX(a,b,c)(a>(b>c?b:c)?a:(b>c?b:c))intmax(inta,intb,intc){if(a>=b&&a>c)return
#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b
PrivateSubForm_Load()DimxAsInteger,yAsInteger,zAsIntegerDimdiyigeAsIntegerDimdiergeAsString,disangeA
#include#includevoidmain(){doublea,b,c,d,s,q;printf("输入三边长");scanf("%d%d%d",&a,&b,&c);d=fabs(a-b);if
inta,b,c;scanf("%d%d%d",&a,&b,&c);if(a
其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望
main() {inta,b,c; printf(“请输入三个整数:”); scanf(“%d,%d,%d”,&a,&b,&c); if(aif(belseprintf(“max=%d\n”,
voidmax(inta,intb,intc){intt;q;t=a>=b?a:b;q=t>=c?t:c;printf("%d\n",q);}