用VB编写程序,找出给定数据范围内所有的回文数
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#define N 10 main(){int num1=0,num2=0,num3=0,i;for(i=0;i<N;i++)scanf("%d
PrivateSubCommand1_Click()DimaAsSingle,bAsSingle,cAsSingleDimdAsSingle,x1AsSingle,x2AsSinglea=InputB
privatesubcommand1_click()dimmaxfori=1to3n=val(inputbox("输入第"&i&"个数"))ifn>maxthenmax=nendifnextprint
ModuleModule1SubMain()DimA(,)AsInteger={{1,2,3,4,5,6,7,8,9,0},{1,2,3,4,5,6,7,8,9,0},{1,2,3,4,5,6,7,8
PrivateFunctionisPrim(n%)AsBoolean'素数判断子过程Dimd%Ifn=2ThenisPrim=True:ExitFunctionFord=2ToSqr(n)IfnMod
PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问:x=x+a*0.2+3000*0.2怎么都乘0.2呀?
PrivateSubCommand1_Click()Dimi%Fori=100To999IfiMod7=0AndMid(CStr(i),2,1)="2"ThenPrintiNextEndSub再问:M
假设矩阵为一个数组a(1tom,1ton)SubMax()Dimb()AsSingle,maxxAsSingleFori=1Tomb(i)=a(i,1)Forj=1TonIfb(i)
Dimb()AsStringb()=Split(a,"")然后判断每一个b数组每一个数据的len即可
PrivateSubForm_Click()DimiAsIntegerDimaa,bbAsIntegerFori=1000To9999aa=iMod100bb=Int(i/100)Ifi=(aa+bb
PrivateSubCommand1_Click()DimsAsString,nAsInteger,iAsIntegerFori=1To100n=n+iNextiPrint"1+2+3+……+100=
PrivateSubCommand1_Click()DimIAsInteger,JAsIntegerDimAAsInteger,BAsIntegerDimSAsString,NAsIntegerDim
PrivateSubCommand1_Click()Fori=1To100Forj=1ToiFork=1TojIfi^2=j^2+k^2ThenPrinti;j;kNextkNextjNextiEnd
dimnasintegerdimsasintgerPrivateSubCommand1_Click()Don=n+1s=s+nLoopuntills>=30000Printn-1EndSu
这一行:DoWhilex>a(p)Andp
'不用这么复杂,你的代码太长没有看,如果一定用你的代码,我再给你修改一下OptionExplicitPrivateSubCommand1_Click()DimiAsLong,arr,nAsLongIf
将六个圆命名为“Oval1”直到“Oval6”在窗体上放6个timer控件.写入如下代码:Private Sub Form_load()'必要的初始化操作Timer1.in
拜托,这么多输入你就用列表啦,用那么多textbox,你不累我看得都累.还有,你要求的是什么尽量用数学的方式表达出来,有图更好至于你的a5d6的问题,是因为你的是字符串运算而不是数值运算,转换一下类型
我HI你吧,等一下